Physics-
General
Easy

Question

on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – F equals rho A open parentheses V subscript 0 end subscript minus u close parentheses to the power of 2 end exponent left square bracket 1 minus c o s invisible function application theta right square bracket Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

Given cross-section area of jet equals 2 cross times 10 to the power of negative 4 end exponent text end text m to the power of 2 end exponent velocity of jet V subscript 0 end subscript equals 10 text end text m divided by s e c., density of liquid equals 1000 text end text k g divided by m subscript blank superscript 3 end superscript comma M a s s of cart equals M equals 10 text end text k g.Velocity of cart at t = 10 sec. is equal to :

  1. 4 m/sec    
  2. 6 m/sec    
  3. 8 m/sec    
  4. 5 m/sec    

The correct answer is: 8 m/sec


    F equals 2 rho A open parentheses V subscript 0 end subscript minus u close parentheses to the power of 2 end exponent u equals text  speed of cart end text
    table row cell m fraction numerator d u over denominator d t end fraction equals 2 rho A open parentheses v subscript 0 end subscript minus u close parentheses to the power of 2 end exponent end cell row cell stretchy integral subscript 0 end subscript superscript u end superscript   fraction numerator d u over denominator open parentheses V subscript 0 end subscript minus u close parentheses to the power of 2 end exponent end fraction equals fraction numerator 2 p A over denominator m end fraction stretchy integral subscript 0 end subscript superscript t end superscript   d t end cell row cell open square brackets fraction numerator 2 rho A over denominator m end fraction equals fraction numerator 2 cross times 10 to the power of 3 end exponent cross times 2 cross times 10 to the power of negative 4 end exponent over denominator 10 end fraction equals fraction numerator 4 over denominator 100 end fraction close square brackets end cell row cell open square brackets fraction numerator 1 over denominator V subscript 0 end subscript minus u end fraction close square brackets subscript 0 end subscript superscript u end superscript equals fraction numerator 2 p A t over denominator m end fraction end cell end table
    table row cell fraction numerator 1 over denominator V subscript 0 end subscript minus u end fraction minus fraction numerator 1 over denominator V subscript 0 end subscript end fraction equals fraction numerator 2 p A t over denominator m end fraction equals fraction numerator 4 t over denominator 100 end fraction end cell row cell text end text text a end text text t end text text end text t equals 10 s e c. rightwards arrow fraction numerator 1 over denominator V subscript 0 end subscript minus u end fraction equals fraction numerator 4 over denominator 10 end fraction plus fraction numerator 1 over denominator 10 end fraction equals fraction numerator 1 over denominator 2 end fraction end cell row cell V subscript 0 end subscript minus u equals 2 u equals 8 m divided by s e c end cell end table

    Related Questions to study

    General
    Physics-

    on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – F equals rho A open parentheses V subscript 0 end subscript minus u close parentheses to the power of 2 end exponent left square bracket 1 minus c o s invisible function application theta right square bracket Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

    Given cross-section area of jet equals 2 cross times 10 to the power of negative 4 end exponent text end text m to the power of 2 end exponent velocity of jet V subscript 0 end subscript equals 10 text end text m divided by s e c., density of liquid equals 1000 text end text k g divided by m subscript blank superscript 3 end superscript comma M a s s of cart equals M equals 10 text end text k g. Initially left parenthesis t equals 0 right parenthesis the force on the cart is equal to :

    on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – F equals rho A open parentheses V subscript 0 end subscript minus u close parentheses to the power of 2 end exponent left square bracket 1 minus c o s invisible function application theta right square bracket Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

    Given cross-section area of jet equals 2 cross times 10 to the power of negative 4 end exponent text end text m to the power of 2 end exponent velocity of jet V subscript 0 end subscript equals 10 text end text m divided by s e c., density of liquid equals 1000 text end text k g divided by m subscript blank superscript 3 end superscript comma M a s s of cart equals M equals 10 text end text k g. Initially left parenthesis t equals 0 right parenthesis the force on the cart is equal to :

    Physics-General
    General
    Physics-

    A cylindrical vessel of 90 cm height is kept filled upto the brim. It has four holes 1, 2, 3, 4 which are respectively at heights of 20cm, 30 cm, 40 cm and 50 cm from the horizontal floor PQ. The water falling at the maximum horizontal distance from the vessel comes from

    A cylindrical vessel of 90 cm height is kept filled upto the brim. It has four holes 1, 2, 3, 4 which are respectively at heights of 20cm, 30 cm, 40 cm and 50 cm from the horizontal floor PQ. The water falling at the maximum horizontal distance from the vessel comes from

    Physics-General
    General
    Physics-

    Two forces F subscript 1 end subscript and F subscript 2 end subscript act on a thin uniform elastic rod placed in space. Force F subscript 1 end subscript acts at right end of the rod and F subscript 2 end subscript acts exactly at centre of the rod as shown (both forces act parallel to length of the rod).
    i) F subscript 1 end subscript causes extension of rod while F subscript 2 end subscript causes compression of rod.
    ii) F subscript 1 end subscript causes extension of rod and F subscript 2 end subscript also causes extension of rod.
    iii) F subscript 1 end subscript causes extension of rod while F subscript 2 end subscript does not change length of rod.
    The correct order of True / False in above statements is

    Two forces F subscript 1 end subscript and F subscript 2 end subscript act on a thin uniform elastic rod placed in space. Force F subscript 1 end subscript acts at right end of the rod and F subscript 2 end subscript acts exactly at centre of the rod as shown (both forces act parallel to length of the rod).
    i) F subscript 1 end subscript causes extension of rod while F subscript 2 end subscript causes compression of rod.
    ii) F subscript 1 end subscript causes extension of rod and F subscript 2 end subscript also causes extension of rod.
    iii) F subscript 1 end subscript causes extension of rod while F subscript 2 end subscript does not change length of rod.
    The correct order of True / False in above statements is

    Physics-General
    parallel
    General
    Physics-

    A rod of length 1000 mm and co-efficient of linear expansion alpha equals 10 to the power of negative 4 end exponent per degree is placed symmetrically between fixed walls separated by 1001 mm. The Young's modulus of the rod is 10 to the power of 11 end exponent N divided by m to the power of 2 end exponent. If the temperature is increased by 20 to the power of ring operator end exponent C, then the stress developed in therod is (in N divided by m to the power of 2 end exponent):

    A rod of length 1000 mm and co-efficient of linear expansion alpha equals 10 to the power of negative 4 end exponent per degree is placed symmetrically between fixed walls separated by 1001 mm. The Young's modulus of the rod is 10 to the power of 11 end exponent N divided by m to the power of 2 end exponent. If the temperature is increased by 20 to the power of ring operator end exponent C, then the stress developed in therod is (in N divided by m to the power of 2 end exponent):

    Physics-General
    General
    Physics-

    A long capillary tube of mass 'pi ' gm, radius 2mm and negligible thickness, is partially immersed in a liquid of surface tension 0.1 N/m. Take angle of contact zero and neglect buoyant force of liquid. The force required to hold the tube vertically, will be - (g = 10 m divided by s to the power of 2 end exponent)

    A long capillary tube of mass 'pi ' gm, radius 2mm and negligible thickness, is partially immersed in a liquid of surface tension 0.1 N/m. Take angle of contact zero and neglect buoyant force of liquid. The force required to hold the tube vertically, will be - (g = 10 m divided by s to the power of 2 end exponent)

    Physics-General
    General
    Physics-

    Assuming the xylem tissues through which water rises from root to the branches in a tree to be of uniform cross-section find the maximum radius of xylum tube in a 10 m high coconut tree so that water can rise to the top. (surface tension of water = 0.1N/m, Angle of contact of water with xylem tube= 60 to the power of ring operator end exponent)

    Assuming the xylem tissues through which water rises from root to the branches in a tree to be of uniform cross-section find the maximum radius of xylum tube in a 10 m high coconut tree so that water can rise to the top. (surface tension of water = 0.1N/m, Angle of contact of water with xylem tube= 60 to the power of ring operator end exponent)

    Physics-General
    parallel
    General
    Physics-

    A block of mass ‘ M ’ area of cross-section ‘A’ & length ‘l’ is placed on smooth horizontal floor. A force ‘ F ’ is applied on the block as shown. If ‘ y’ is young modulus of material, then total extension in the block will be:

    A block of mass ‘ M ’ area of cross-section ‘A’ & length ‘l’ is placed on smooth horizontal floor. A force ‘ F ’ is applied on the block as shown. If ‘ y’ is young modulus of material, then total extension in the block will be:

    Physics-General
    General
    Physics-

    In determination of young modulus of elasticity of wire, a force is applied and extension is recorded. Initial length of wire is ‘ 1 m’. The curve between extension and stress is depicted then young modulus of wire will be:

    In determination of young modulus of elasticity of wire, a force is applied and extension is recorded. Initial length of wire is ‘ 1 m’. The curve between extension and stress is depicted then young modulus of wire will be:

    Physics-General
    General
    Physics-

    A space 2.5 cm wide between two large plane surfaces is filled with oil. Force required to drag a very thin plate of area 0.5 m to the power of 2 end exponent just midway the surfaces at a speed of 0.5 m/sec is 1N. The coefficient of viscosity in kg–sec/ m to the power of 2 end exponent is :

    A space 2.5 cm wide between two large plane surfaces is filled with oil. Force required to drag a very thin plate of area 0.5 m to the power of 2 end exponent just midway the surfaces at a speed of 0.5 m/sec is 1N. The coefficient of viscosity in kg–sec/ m to the power of 2 end exponent is :

    Physics-General
    parallel
    General
    Physics-

    Shape of the meniscus formed by two liquids when capillaries are dipped in them are shown. In I it is hemispherical where as in II it is flat. Pick correct statement regarding contact angles formed by the liquids in both situations

    Shape of the meniscus formed by two liquids when capillaries are dipped in them are shown. In I it is hemispherical where as in II it is flat. Pick correct statement regarding contact angles formed by the liquids in both situations

    Physics-General
    General
    Physics-

    A capillary of the shape as shown is dipped in a liquid. Contact angle between the liquid and the capillary is 0 to the power of 0 end exponent and effect of liquid inside the meniscus is to be neglected. T is surface tension of the liquid, r is radius of the meniscus, g is acceleration due to gravity and rho is density of the liquid then height h in equilibrium is

    A capillary of the shape as shown is dipped in a liquid. Contact angle between the liquid and the capillary is 0 to the power of 0 end exponent and effect of liquid inside the meniscus is to be neglected. T is surface tension of the liquid, r is radius of the meniscus, g is acceleration due to gravity and rho is density of the liquid then height h in equilibrium is

    Physics-General
    General
    Physics-

    The figure shows a soap film in which a closed elastic thread is lying. The film inside the thread is pricked. Now the sliding wire is moved out so that the surface area increases. The radius of the circle formed by elastic thread will

    The figure shows a soap film in which a closed elastic thread is lying. The film inside the thread is pricked. Now the sliding wire is moved out so that the surface area increases. The radius of the circle formed by elastic thread will

    Physics-General
    parallel
    General
    Physics-

    A steady stream of water falls straight down from a pipe as shown. Assume the flow is incompressible, then

    A steady stream of water falls straight down from a pipe as shown. Assume the flow is incompressible, then

    Physics-General
    General
    Physics-

    A square box of water has a small hole located in one of the bottom corner. When the box is full and placed on a level surface, complete opening of the hole results in a flow of water with a speed V subscript 0 end subscript, as shown in figure (A). When the box is still half empty, it is tilted by 45 to the power of 0 end exponent so that the hole is at the lowest point. Now the water will flow out with a speed of

    A square box of water has a small hole located in one of the bottom corner. When the box is full and placed on a level surface, complete opening of the hole results in a flow of water with a speed V subscript 0 end subscript, as shown in figure (A). When the box is still half empty, it is tilted by 45 to the power of 0 end exponent so that the hole is at the lowest point. Now the water will flow out with a speed of

    Physics-General
    General
    Physics-

    A non uniform cylinder of mass m, length l and radius r is having its cetnre of mass at a distance lambda /4 from the centre and lying on the axis of the cylinder. The cylinder is kept in a liquid of uniform density rho . The moment of inertia of the rod about the centre of mass is I. The angular acceleration of point A relative to point B just after the rod is released from the position shown in figure is

    A non uniform cylinder of mass m, length l and radius r is having its cetnre of mass at a distance lambda /4 from the centre and lying on the axis of the cylinder. The cylinder is kept in a liquid of uniform density rho . The moment of inertia of the rod about the centre of mass is I. The angular acceleration of point A relative to point B just after the rod is released from the position shown in figure is

    Physics-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.