Physics-
General
Easy

Question

One ice skater of mass m moves with speed 2v to the right, while another of the same mass m moves with speed v toward the left, as shown in figure I. Their paths are separated by a distance b. At t = 0, when they are both at x = 0, they grasp a pole of length b and negligible mass. For t > 0, consider the system as a rigid body of two masses m separated by distance b, as shown in figure II. Which of the following is the correct formula for the motion after t = 0 of the skater initially at y=b/2?

  1. x equals 2 v t comma y equals b divided by 2    
  2. x equals v t plus 0.5 b s i n invisible function application left parenthesis 3 v t divided by b right parenthesis comma y equals 0.5 b c o s invisible function application left parenthesis 3 v t divided by b right parenthesis    
  3. x equals 0.5 v t plus 0.5 b s i n invisible function application left parenthesis 3 v t divided by b right parenthesis comma y equals 0.5 b c o s invisible function application left parenthesis 3 v t divided by b right parenthesis    
  4. x equals 0.5 v t plus 0.5 bsin invisible function application open parentheses fraction numerator 6 v t over denominator b end fraction close parentheses comma y equals 0.5 bcos invisible function application open parentheses fraction numerator 6 v t over denominator b end fraction close parentheses    

The correct answer is: x equals v t plus 0.5 b s i n invisible function application left parenthesis 3 v t divided by b right parenthesis comma y equals 0.5 b c o s invisible function application left parenthesis 3 v t divided by b right parenthesis

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