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Physics-

General

Easy

Question

One mole of an ideal monoatomic gas undergoes a cyclic process as shown in figure. Temperature at point 1 = 300 K and process 2-3 is isothermal. Net work done by gas in complete cycle is

$(9 (n 3 + 12) P_{0} V_{0}$
$(9 l n 3 + 4) P_{0} V_{0}$
$(9 l n 3 - 4) P_{0} V_{0}$
$(9 (n 3 - 8) P_{0} V_{0}$

The correct answer is: $left parenthesis 9 l n 3 minus 4 right parenthesis P subscript 0 end subscript V subscript 0 end subscript$

$W equals W subscript 12 end subscript plus W subscript 2 s end subscript plus W subscript 31 end subscript equals fraction numerator 1 over denominator 2 end fraction open parentheses 4 P subscript 0 end subscript close parentheses open parentheses 2 V subscript 0 end subscript close parentheses plus n R T divided by n left parenthesis 3 right parenthesis minus P subscript 0 end subscript open parentheses 8 V subscript 0 end subscript close parentheses equals negative 4 P subscript 0 end subscript V subscript 0 end subscript plus 9 P subscript 0 end subscript V subscript 0 end subscript open parentheses n 3 equals left parenthesis 9 n 3 minus 4 right parenthesis P subscript 0 end subscript V subscript o end subscript close$

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