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Physics

Mechanics

Easy

Question

The acceleration of a body due to the attraction of the earth (radius R) at a distance 2 R from the surface of the earth is (g= acceleration due to gravity at the surface of the earth)

$\frac{g}{9}$
$\frac{g}{3}$
$\frac{g}{4}$
$g$

The correct answer is: $g over 9$

$table attributes columnalign left end attributes row cell g to the power of apostrophe over g equals open parentheses fraction numerator R over denominator R plus h end fraction close parentheses squared equals open parentheses fraction numerator R over denominator R plus 2 R end fraction close parentheses squared equals 1 over 9 end cell row cell therefore g to the power of apostrophe equals g over 9 end cell end table$

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