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Physics-

General

Easy

Question

The dimensions of capacitance are

M^-1L^-2TI²
M^-1L^-2T²I^-2
ML^-2T^-2I^-1
M^-1L^-2T⁴I²

The correct answer is: M^-1L^-2T⁴I²

C = $fraction numerator Q over denominator W divided by Q end fraction equals fraction numerator Q to the power of 2 end exponent cross times T to the power of 2 end exponent over denominator W cross times T to the power of 2 end exponent end fraction equals fraction numerator T to the power of 2 end exponent over denominator W to the power of 2 end exponent end fraction I to the power of 2 end exponent$
= $fraction numerator T to the power of 2 end exponent I to the power of 2 end exponent over denominator M L to the power of 2 end exponent T to the power of negative 2 end exponent end fraction$
= M^–1L^–2T⁴I²

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