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Physics-

General

Easy

Question

The electric potential (V) in volts varies with x (in metre) according to the relation $V equals 5 plus 4 x to the power of 2 end exponent$ . The force experienced by a negative charge of $2 mu C$ located at x=0.5m is

$2 \times 10^{- 6} N$
$4 \times 10^{- 6} N$
$6 \times 10^{- 6} N$
$8 \times 10^{- 6} N$

The correct answer is: $8 cross times 10 to the power of negative 6 end exponent N$

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