Question
The ends of a stretched wire of length L are fixed at x = 0 and x = L. In one experiment the displacement of the wire is y1 = A sin 
sin ωt and energy is E1 and in other experiment its displacement 
and energy is E2
- E2 = E1
- E2 = 2E1
- E2 = 4E1
- E2 = 16E1
The correct answer is: E2 = 4E1
Related Questions to study
S1 and S2 are two coherent currents sources of radiations separated by distance 100.25 λ , where l is the wave length of radiation. S1 leads S2 in phase by Π/ 2 . A and B are two points on the line joining S1 and S2 as shown in figure. The ratio of amplitudes of sources S1 and S2 are in the ratio 1 : 2. The ratio of intensity at A to that of B 
is
S1 and S2 are two coherent currents sources of radiations separated by distance 100.25 λ , where l is the wave length of radiation. S1 leads S2 in phase by Π/ 2 . A and B are two points on the line joining S1 and S2 as shown in figure. The ratio of amplitudes of sources S1 and S2 are in the ratio 1 : 2. The ratio of intensity at A to that of B is
The amplitude of a wave disturbance propagating in the positive x–direction is given by y= 
at t= 0 and 
t = 2s, where x and y are in meter. Assuming that the shape of the wave disturbance does not change during the propagation, the speed of the wave is
The amplitude of a wave disturbance propagating in the positive x–direction is given by y= at t= 0 and t = 2s, where x and y are in meter. Assuming that the shape of the wave disturbance does not change during the propagation, the speed of the wave is
Statement-1 : Two sound waves of equal intensity I produced beats. The maximum intensity of sound produced in beats is 4I
Statement-2 : If two waves of amplitudes a1 and a2 superpose, the maximum amplitude of the resultant wave = a1 + a2
Statement-1 : Two sound waves of equal intensity I produced beats. The maximum intensity of sound produced in beats is 4I
Statement-2 : If two waves of amplitudes a1 and a2 superpose, the maximum amplitude of the resultant wave = a1 + a2
Statement – 1: Two tuning forks having frequency 410 Hz and 524 Hz are kept close and made to vibrate. Beats will not be heard
Statement – 2 : Sound waves superimpose only when the frequencies of superposing waves are equal or nearly equal
Statement – 1: Two tuning forks having frequency 410 Hz and 524 Hz are kept close and made to vibrate. Beats will not be heard
Statement – 2 : Sound waves superimpose only when the frequencies of superposing waves are equal or nearly equal
Statement – 1: In case of beats, intensity of sound at some positions in space remains maximum and at others, it remains minimum
Statement – 2: Beat are formed due to superposition of sound waves of unequal frequencies
Statement – 1: In case of beats, intensity of sound at some positions in space remains maximum and at others, it remains minimum
Statement – 2: Beat are formed due to superposition of sound waves of unequal frequencies
STATEMENT – 1 : In the case of stationary wave, a person hear a loud sound at the nodes as compared to the antinodes. Because
STATEMENT – 2 : In a stationary wave all the particles of the medium vibrate in phase
STATEMENT – 1 : In the case of stationary wave, a person hear a loud sound at the nodes as compared to the antinodes. Because
STATEMENT – 2 : In a stationary wave all the particles of the medium vibrate in phase
STATEMENT – 1 : When standing waves are produced in a closed organ pipe, the pressure at the closed end is a constant. Because
STATEMENT – 2 : The closed end corresponds to a node and hence the pressure is constant
STATEMENT – 1 : When standing waves are produced in a closed organ pipe, the pressure at the closed end is a constant. Because
STATEMENT – 2 : The closed end corresponds to a node and hence the pressure is constant
STATEMENT – 1 : Soldiers are asked to break steps while crossing the bridge to avoid resonance situation. Because
STATEMENT – 2 : When frequency of two oscillating system are equal, their amplitude of vibration become very high
STATEMENT – 1 : Soldiers are asked to break steps while crossing the bridge to avoid resonance situation. Because
STATEMENT – 2 : When frequency of two oscillating system are equal, their amplitude of vibration become very high
STATEMENT – 1 : If an observer places his ear at the end of a long steel pipe, he can hear two distinct sounds, when a workman hammers the other end of the pipe. Because
STATEMENT – 2 : Longitudinal as well as transverses wave can be propagated in steel
STATEMENT – 1 : If an observer places his ear at the end of a long steel pipe, he can hear two distinct sounds, when a workman hammers the other end of the pipe. Because
STATEMENT – 2 : Longitudinal as well as transverses wave can be propagated in steel
STATEMENT – 1 :speed of sound in air was found wrong because, he assumed process as isothermal. Because
STATEMENT – 2 : Flow of sound wave in a medium is very fast. Quick process suppress heat exchange, hence this process must be adiabatic in nature
STATEMENT – 1 :speed of sound in air was found wrong because, he assumed process as isothermal. Because
STATEMENT – 2 : Flow of sound wave in a medium is very fast. Quick process suppress heat exchange, hence this process must be adiabatic in nature
STATEMENT – 1 : The velocity of sound in air, at constant temperature, does not depend on the ambient pressure. Because
STATEMENT – 2 : This is a consequence of the fact that the velocity of sound is a function of the ratio p/p but as P increases, 
increases by the same factor at constant temperature
STATEMENT – 1 : The velocity of sound in air, at constant temperature, does not depend on the ambient pressure. Because
STATEMENT – 2 : This is a consequence of the fact that the velocity of sound is a function of the ratio p/p but as P increases, increases by the same factor at constant temperature
STATEMENT – 1 : The basic of Laplace correction was the exchange of heat between the region of compression and rarefaction in air is not possible. Because
STATEMENT – 2 : Air is a bad conductor of heat and velocity of sound in air is large
STATEMENT – 1 : The basic of Laplace correction was the exchange of heat between the region of compression and rarefaction in air is not possible. Because
STATEMENT – 2 : Air is a bad conductor of heat and velocity of sound in air is large
