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Physics-

General

Easy

Question

The field pattern is shown due to two point charges 1 and 2. Then q₁/q₂ =

$- \frac{1}{2}$
$- 2$
$\frac{1}{2} .$
none of these

The correct answer is: $negative fraction numerator 1 over denominator 2 end fraction$

Related Questions to study

Statement : 1 The value of k for which the equation $x to the power of 2 end exponent plus k x minus fraction numerator pi over denominator 2 end fraction plus s i n to the power of negative 1 end exponent invisible function application open parentheses x to the power of 2 end exponent minus 6 x plus 10 close parentheses plus c o s to the power of negative 1 end exponent invisible function application open parentheses x to the power of 2 end exponent minus 6 x plus 10 close parentheses equals 0$ Has a real solution is -3.
Statement : 2 $s i n to the power of negative 1 end exponent invisible function application x plus c o s to the power of negative 1 end exponent invisible function application x equals fraction numerator pi over denominator 2 end fraction comma text for all end text x element of R$

Statement : 1 The value of k for which the equation $x to the power of 2 end exponent plus k x minus fraction numerator pi over denominator 2 end fraction plus s i n to the power of negative 1 end exponent invisible function application open parentheses x to the power of 2 end exponent minus 6 x plus 10 close parentheses plus c o s to the power of negative 1 end exponent invisible function application open parentheses x to the power of 2 end exponent minus 6 x plus 10 close parentheses equals 0$ Has a real solution is -3.
Statement : 2 $s i n to the power of negative 1 end exponent invisible function application x plus c o s to the power of negative 1 end exponent invisible function application x equals fraction numerator pi over denominator 2 end fraction comma text for all end text x element of R$

Six charges of equal magnitude, 3 positive and 3 negative are to be placed on PQRSTU corners of a regular hexagon, such that field at the centre is double that of what it would have been if only one +ve charge is placed at R.

Six charges of equal magnitude, 3 positive and 3 negative are to be placed on PQRSTU corners of a regular hexagon, such that field at the centre is double that of what it would have been if only one +ve charge is placed at R.

Physics-General

The ratio of q and Q so as to make the system in equilibrium is

The ratio of q and Q so as to make the system in equilibrium is

Physics-General

parallel

A positive charge Q is placed at the centre of a square of side l. Then the net force acting on the central charge Q due to the other four charges Q, 2Q ,3Q and 4Q placed at the vertices of the square is

A positive charge Q is placed at the centre of a square of side l. Then the net force acting on the central charge Q due to the other four charges Q, 2Q ,3Q and 4Q placed at the vertices of the square is

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Let $alpha comma beta comma gamma greater than 0$ and $alpha plus beta plus gamma equals fraction numerator n over denominator 2 end fraction$
Assertion(A) : If p = 5+tanthen the maximum value of $square root of p plus square root of q plus square root of r text is end text 3 square root of 5$
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Reason (R) : tan $alpha t a n invisible function application beta$ +tan $beta$ tan $gamma$ + tan $y$ tan $C$ =1

If the sum of two unit vectors is a unit vector, then the magnitude of their difference is

If the sum of two unit vectors is a unit vector, then the magnitude of their difference is

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parallel

Two forces each numerically equal to 10 dynes are acting as shown in the following figure, then the resultant is

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Consider the function f(x) = cosx + 2cos kx, k Q, k 0
STATEMENT1 : The equation f(x) = 3 has infinite number of solutions. because
STATEMENT2 : The function f is periodic.

Consider the function f(x) = cosx + 2cos kx, k Q, k 0
STATEMENT1 : The equation f(x) = 3 has infinite number of solutions. because
STATEMENT2 : The function f is periodic.

Statement1: Number of ordered pairs ( $theta$ , x) satisfying 2sin $theta$ = e^x + e^x, $theta$ [0, 3θ] is 2.
Statement2: Number of values of x for which sin2x + cos4x = 2 is zero.

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Statement2: Number of values of x for which sin2x + cos4x = 2 is zero.

parallel

If $open vertical bar 2 t a n to the power of negative 1 end exponent invisible function application x plus s i n to the power of negative 1 end exponent invisible function application fraction numerator 2 x over denominator 1 plus x to the power of 2 end exponent end fraction close vertical bar$ is independent of x then

If $open vertical bar 2 t a n to the power of negative 1 end exponent invisible function application x plus s i n to the power of negative 1 end exponent invisible function application fraction numerator 2 x over denominator 1 plus x to the power of 2 end exponent end fraction close vertical bar$ is independent of x then

The displacement vector is represented by

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A simple pendulum of time period 2 sec the length of pendulum is

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parallel

An echo will be heard if the minimum distance between the source of sound and the obstacle is

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The coefficient of xⁿ in the expansion of $fraction numerator 1 over denominator open parentheses 1 minus x close parentheses open parentheses 3 minus x close parentheses end fraction$ is

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Coefficient of x⁵ in the expansion of (1 + x²)⁵(1 + x)⁴ is

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parallel

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