Physics-
General
Easy

Question

The first ionization potentials open parentheses e V close parentheses of B e and B respectively are

  1. 8.29 e V, 9.32 e V  
  2. 9.32 e V, 9.32 e V  
  3. 8.29 e V, 8.29 e V  
  4. 9.32 e V, 8.29 e V  

The correct answer is: 9.32 e V, 8.29 e V


    First I.P. of B e greater than B because of stable n s to the power of 2 end exponent configuration.

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