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Question
The gas left in the vessel will be 2g of hydrogen i.e. number of molesnull
- Monoatomic
- Diatomic
- A mixture of monoatomic and diatomic
- A mixture of diatomic and polyatomic
The correct answer is: A mixture of monoatomic and diatomic
For adiabatic process TVg–1 = constant
null
For monoatomic gasnull
For diatomic gasnull
Hence, the gas must be a mixture of monoatomic & diatomic gas.
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