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Physics

Mechanics

Easy

Question

The mean radius of the earth is R, its angular speed on its own axis is $omega$ and the acceleration due to gravity at earth's surface is g. The cube of the radius of the orbit of a geo-stationary satellite will be

$R^{2} g / ω ∣$
$R^{2} ω^{2} / g$
$Rg / ω^{2}$ $R^{2} g / ω^{2}$

The correct answer is: $Rg invisible function application divided by omega squared$ $R squared g divided by omega squared$

$table attributes columnalign left columnspacing 1em rowspacing 4 pt end attributes row cell T equals fraction numerator 2 pi r to the power of 3 divided by 2 end exponent over denominator square root of G M end root end fraction end cell row cell not stretchy rightwards double arrow r cubed equals fraction numerator T squared G M over denominator 4 pi squared end fraction equals fraction numerator R squared g over denominator omega squared end fraction end cell end table$

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