Physics-
General
Easy

Question

The minimum velocity open parentheses i n blank m s to the power of negative 1 end exponent close parentheses with which a car driver must traverse a flat curve of radius of 150 m and coefficient of friction 0.6 to avoid skidding is

  1. 60  
  2. 30  
  3. 15  
  4. 25  

The correct answer is: 30


    Using the relation
    fraction numerator m v to the power of 2 end exponent over denominator r end fraction equals mu R comma blank R equals m g
    fraction numerator m v to the power of 2 end exponent over denominator r end fraction equals mu m g ⟹ v to the power of 2 end exponent equals mu r g
    v to the power of 2 end exponent equals 0.6 cross times 150 cross times 10
    v equals 30 m s to the power of negative 1 end exponent

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