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Question

The moment of inertia of a body about a given axis is 1.2 kg × m2. Initially, the body is at rest. In order to produce a rotational KE of 1500 joule, an angular acceleration of 25 rad/sec2 must be applied about that axis for a duration of -

  1. 4 s  
  2. 2 s  
  3. 8 s  
  4. 10 s  

The correct answer is: 2 s


    KR = fraction numerator 1 over denominator 2 end fraction I2 = fraction numerator 1 over denominator 2 end fraction I (t)2 = fraction numerator 1 over denominator 2 end fraction I2t2
    1500 = fraction numerator 1 over denominator 2 end fraction × 1.2 × (25)2t2
    or t2 = 4 or t = 2s

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