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Physics-

General

Easy

Question

The moments of inertia of two freely rotating bodies $A$ and $B$ are $I subscript A end subscript$ and $I subscript B end subscript$ respectively. $I subscript A end subscript greater than I subscript B end subscript$ and their angular momenta are equal. If $K subscript A end subscript$ and $K subscript B end subscript$ are their kinetic energies, then

$K_{A} = K_{B}$
$K_{A} \neq K_{B}$
$K_{A} < K_{B}$
$K_{A} = 2 K_{B}$

The correct answer is: $K subscript A end subscript less than K subscript B end subscript$

Kinetic energy $E equals fraction numerator L to the power of 2 end exponent over denominator 2 I end fraction$
If angular momenta are equal, then $E proportional to fraction numerator 1 over denominator I end fraction$
Kinetic energy $E equals K$ (given in problem)
If $I subscript A end subscript greater than I subscript B end subscript$ then $K subscript A end subscript less than K subscript B end subscript$ .

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