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Physics-

General

Easy

Question

The mutual inductance between a primary and secondary circuits is $0.5 blank H$ . The resistances of the primary and the secondary circuits are $20 blank o h m s$ and $5 blank o h m s$ respectively. To generate a current of $0.4 blank A$ in the secondary, current in the primary must be changed at the rate of

$4.0 A / s$
$16.0 A / s$
$1.6 A / s$
$8.0 A / s$

The correct answer is: $4.0 blank A divided by s$

$e subscript 2 end subscript equals M fraction numerator d i subscript 1 end subscript over denominator d t end fraction rightwards double arrow i subscript 2 end subscript R subscript 2 end subscript equals M fraction numerator d i subscript 1 end subscript over denominator d t end fraction rightwards double arrow 0.4 cross times 5 equals 0.5 cross times fraction numerator d i subscript 1 end subscript over denominator d t end fraction$
$rightwards double arrow fraction numerator d i subscript 1 end subscript over denominator d t end fraction equals 4 blank A divided by s e c$

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