Physics
Fluid-Mechanics
Easy

Question

The radii of two soap bubbles are R1 and R2 respectively. The ratio of masses of air in then will be

  1. fraction numerator R subscript 1 superscript 3 over denominator R subscript 2 superscript 3 end fraction
  2. fraction numerator R subscript 2 superscript 3 over denominator R subscript 1 superscript 3 end fraction
  3. open parentheses fraction numerator P plus fraction numerator 4 T over denominator R subscript 1 end fraction over denominator P plus fraction numerator 4 T over denominator R subscript 2 end fraction end fraction close parentheses fraction numerator R subscript 1 superscript 3 over denominator R subscript 2 superscript 3 end fraction
  4. open parentheses fraction numerator P plus fraction numerator 4 T over denominator R subscript 2 end fraction over denominator P plus fraction numerator 4 T over denominator R subscript 1 end fraction end fraction close parentheses fraction numerator R subscript 2 superscript 3 over denominator R subscript 1 superscript 3 end fraction

The correct answer is: open parentheses fraction numerator P plus fraction numerator 4 T over denominator R subscript 1 end fraction over denominator P plus fraction numerator 4 T over denominator R subscript 2 end fraction end fraction close parentheses fraction numerator R subscript 1 superscript 3 over denominator R subscript 2 superscript 3 end fraction

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