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Physics-

General

Easy

Question

The self induced emf in a coils of 0.4 henry self inductance when current in it is changing at the rate of 50As^-1, is

$8 \times 10^{- 4}$ V
$8 \times 10^{- 3} V$
200 V
500 V

The correct answer is: 200 V

The induced emf is given by
$open vertical bar e close vertical bar equals open parentheses L fraction numerator d i over denominator d t end fraction close parentheses$
$blank equals 0.4 cross times 500 equals 200 blank V$

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