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Physics-

General

Easy

Question

The shortest wavelength of X-rays emitted from an X-rays tube depends upon

Nature of the gas in the tube
Voltage applied to tube
Current in the tube
Nature of target of the tube

The correct answer is: Voltage applied to tube

$e V equals h c divided by lambda$
Or $lambda equals h c divided by e V blank i e comma lambda proportional to 1 divided by V$

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The refractive index and the permeability of a medium are respectively $blank 1.5 blank a n d blank 5 blank cross times blank 10 to the power of negative 7 end exponent H m to the power of negative 1 end exponent$ . The relative permittivity of the medium is nearly

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Maxwell in his famous equation of electromagnetism introduced the concept of

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In a phase electromagnetic wave, the electric filed oscillates sinusoidally at a frequency of $2.0 cross times 10 to the power of 10 end exponent$ Hz and amplitude $48 blank V m to the power of negative 1 end exponent$ . The wavelength of the wave is

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A plane electromagnetic wave of intensity 10 $W m to the power of negative 2 end exponent$ strikes a small mirror of area $20 blank c m to the power of 2 end exponent$ , held perpendicular to the approaching wave. The radiation force on the mirror will be

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If $epsilon subscript 0 end subscript$ and $mu subscript 0 end subscript$ represent the permittivity and permeability of vacuum and $epsilon$ and $mu$ represent the permittivity and permeability of medium, then refractive index of the medium is given by

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