Physics-
General
Easy

Question

The square loop ABCD, carrying a current i, is placed in uniform magnetic field B, as shown. The loop can rotate about the axis XX'. The plane of the loop makes and angle theta (theta < 90°) with the direction of B. Through what angle will the loop rotate by itself before the torque on it becomes zero

  1. q    
  2. 90°– theta    
  3. 90° + theta    
  4. 180°– theta    

The correct answer is: 90° + theta


    In the position shown, AB is outside and CD is inside the plane of the paper. The Ampere force on AB acts into the paper. The torque on the loop will be clockwise, as seen from above. The loop must rotate through an angle left parenthesis 9 0 to the power of o end exponent plus theta right parenthesis before the plane of the loop becomes normal to the direction of the direction of B and the torque becomes zero.

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