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Physics-

General

Easy

Question

The variation of electric potential with distance d from a fixed point is as shown in the figure. The electric intensity at d=5m is

$2.5 V m^{- 1}$
$- 2.5 V m^{- 1}$
$0.4 V m^{- 1}$
$- 0.4 V m^{- 1}$

The correct answer is: $2.5 V m to the power of negative 1 end exponent$

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