Physics-
General
Easy

Question

The variation of potential energy of harmonic oscillator is as shown in figure. The spring constant is

  1. 1 '102 N/m    
  2. 150 N/m    
  3. 0.667 ' 102 N/m    
  4. 3 ' 102 N/m    

The correct answer is: 150 N/m


    Total potential energy = 0.04 J
    Resting potential energy =0.01 J
    Maximum kinetic energy =(0.04–0.01)
    equals 0.03 J equals fraction numerator 1 over denominator 2 end fraction m   omega to the power of 2 end exponent a to the power of 2 end exponent equals fraction numerator 1 over denominator 2 end fraction k a to the power of 2 end exponent
    0.03 equals fraction numerator 1 over denominator 2 end fraction cross times k cross times open parentheses fraction numerator 20 over denominator 1000 end fraction close parentheses to the power of 2 end exponent
    k equals 0.06 cross times 2500   N divided by m equals 150   N divided by m

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