Physics-
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Easy

Question

Two identical balls A and B each of mass 0.1 kg are attached to two identical massless springs. The spring mass system is constrained to move inside a rigid smooth pipe bent in the form of a circle as shown in the figure. The pipe is fixed in a horizontal plane. The centres of the balls can move in a circle of radius 0.06 m. Each spring has a natural length of 0.06p m and force constant 0.1N/m. Initially both the balls are displaced by an angle theta equals pi divided by 6 radian with respect to the diameter P Q of the circle and released from rest. The frequency of oscillation of the ball B is

  1. pi H z    
  2. fraction numerator 1 over denominator pi end fraction H z    
  3. 2 pi H z    
  4. fraction numerator 1 over denominator 2 pi end fraction H z    

The correct answer is: fraction numerator 1 over denominator pi end fraction H z


    As here two masses are connected by two springs, this problem is equivalent to the oscillation of a reduced mass m subscript r end subscript of a spring of effective spring constant.
    T equals 2 pi square root of fraction numerator m subscript r end subscript over denominator K subscript e f f. end subscript end fraction end root
    Here m subscript r end subscript equals fraction numerator m subscript 1 end subscript m subscript 2 end subscript over denominator m subscript 1 end subscript plus m subscript 2 end subscript end fraction equals fraction numerator m over denominator 2 end fraction Þ K subscript e f f. end subscript equals K subscript 1 end subscript plus K subscript 2 end subscript equals 2 K
    \ n equals fraction numerator 1 over denominator 2 pi end fraction square root of fraction numerator K subscript e f f. end subscript over denominator m subscript r end subscript end fraction end root equals fraction numerator 1 over denominator 2 pi end fraction square root of fraction numerator 2 K over denominator m end fraction cross times 2 end root equals fraction numerator 1 over denominator pi end fraction square root of fraction numerator K over denominator m end fraction end root equals fraction numerator 1 over denominator pi end fraction square root of fraction numerator 0.1 over denominator 0.1 end fraction end root equals fraction numerator 1 over denominator pi end fraction H z

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