Physics
Grade-8
Easy

Question

There are two cars, car A and car B. Mass of car A is 10000 kg, travelling at 30 fraction numerator m over denominator s end fraction collide with car B of mass 30000 kg travelling at 20 fraction numerator m over denominator s end fraction in same direction. After collision, the velocity of car A becomes 40 fraction numerator m over denominator s end fraction. Calculate the velocity of car B after the collision?

  1. fraction numerator 50 over denominator 3 end fraction fraction numerator m over denominator s end fraction    
  2. fraction numerator 50 over denominator 3 end fraction fraction numerator m over denominator s end fraction    
  3. fraction numerator 53 over denominator 3 end fraction fraction numerator m over denominator s end fraction    
  4. fraction numerator 47 over denominator 3 end fraction fraction numerator m over denominator s end fraction    

hintHint:

The formula for the law of conservation of momentum is: m 1 u 1 + m 2 u 2 = m 1 v 1 + m 2 v 2.

The correct answer is: fraction numerator 50 over denominator 3 end fraction fraction numerator m over denominator s end fraction


    The formula for the law of conservation of momentum is: m 1 u 1 + m 2 u 2 = m 1 v 1 + m 2 v 2.
    10000 cross times 30 plus 30000 cross times 20 equals 10000 cross times 40 plus 30000 cross times v 2
v 2 equals 50 over 3 m divided by s

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