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Three particles A, B and C situated at vertices of an equilateral triangle, all moving with same constant speed such that A always move towards B, B always towards C and C always towards A. Initial seperation between each of the particle is a. O is the centroid of the triangle. Distance covered by particle A when it completes one revolution around O is

  1. 2 a open parentheses 1 minus e to the power of negative 2 square root of 3 pi end exponent close parentheses    
  2. fraction numerator 2 a over denominator 3 end fraction open parentheses 1 minus e to the power of negative 2 square root of 3 pi end exponent close parentheses    
  3. a open parentheses 1 plus e to the power of negative 2 square root of 3 pi end exponent close parentheses    
  4. fraction numerator 2 a over denominator 3 end fraction open parentheses 1 minus e to the power of negative square root of 3 pi end exponent close parentheses    

The correct answer is: fraction numerator 2 a over denominator 3 end fraction open parentheses 1 minus e to the power of negative 2 square root of 3 pi end exponent close parentheses



    fraction numerator d r over denominator d t end fraction equals negative v c o s invisible function application 30 to the power of ring operator end exponent equals negative fraction numerator square root of 3 over denominator 2 end fraction V
    r fraction numerator d theta over denominator d t end fraction equals vsin invisible function application 30 to the power of ring operator end exponent equals fraction numerator v over denominator 2 end fraction
    fraction numerator 1 over denominator r end fraction fraction numerator d r over denominator d theta end fraction equals negative square root of 3
    stretchy integral subscript r end subscript superscript r end superscript   fraction numerator d r over denominator r end fraction equals negative square root of 3 stretchy integral subscript 0 end subscript superscript theta end superscript   d theta rightwards double arrow r equals r subscript 0 end subscript e to the power of negative square root of 3 theta end exponent
    When A completes one revolution  = 2
    Time taken t=blank fraction numerator r subscript 0 end subscript open parentheses 1 minus e to the power of negative 2 square root of 3 pi end exponent close parentheses over denominator square root of 3 v divided by 2 end fraction
    Distance travelled D = vt = open parentheses 1 minus e to the power of negative 2 square root of 3 pi end exponent close parentheses
    D equals fraction numerator 2 a over denominator 3 end fraction open parentheses 1 minus e to the power of negative 2 square root of 3 pi end exponent close parentheses

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