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Physics-

General

Easy

Question

Two cells of emf $E subscript 1 end subscript$ and $E subscript 2 end subscript$ are connected to two resistors $R subscript 1 end subscript$ and $R subscript 2 end subscript$ as shown. If $E subscript 2 end subscript$ is short circuited then currents through $R subscript 1 end subscript$ and $R subscript 2 end subscript$ are

$\frac{E_{1}}{R_{2}}, 0$
$0, \frac{E_{1}}{R_{2}}$
$\frac{E_{1}}{R_{1}}, 0$
$0, \frac{E_{1}}{R_{1}}$

The correct answer is: $fraction numerator E subscript 1 end subscript over denominator R subscript 1 end subscript end fraction comma 0$

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