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Question

Two large parallel plates are connected with the terminal of 100 V power supply. These plates have a fine hole at the centre. An electron having energy 200 eV is so directed that it passes through the holes. When it comes out it's de-Broglie wavelength is

  1. 1.22 Å    
  2. 1.75 Å    
  3. 2 Å    
  4. None of these    

The correct answer is: 1.22 Å


    Energy of the electron, when it comes out from the second plate = 200 eV – 100 eV = 100 eV
    Hence accelerating potential difference = 100 V
    lambda subscript E l e c t r o n end subscript equals fraction numerator 12.27 over denominator square root of V end fraction equals fraction numerator 12.27 over denominator square root of 100 end fraction equals 1.23 Å

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