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Question

Two loops P and Q are made from a uniform wire. The radii of P and Q are r1 and r2 respectively, and their moments of inertia are I1 and I2 respectively. If I2 = 4I1 , then fraction numerator r subscript 2 end subscript over denominator r subscript 1 end subscript end fraction equals –

  1. 42/3  
  2. 41/3  
  3. 4–2/3  
  4. 4–1/3  

The correct answer is: 41/3


    I = MR2 = (2RAd)R2
    or I  R3
    or R I1/3
    or fraction numerator R subscript 2 end subscript over denominator R subscript 1 end subscript end fraction = open parentheses fraction numerator I subscript 2 end subscript over denominator I subscript 1 end subscript end fraction close parentheses to the power of 1 divided by 3 end exponent = open parentheses fraction numerator 4 over denominator 1 end fraction close parentheses to the power of 1 divided by 3 end exponent

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