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General
Easy
Question
Two loudspeakers L1 and L2 driven by a common oscillator and amplifier, are arranged as shown. The frequency of the oscillator is gradually increased from zero and the detector at D records a series of maxima and minima. If the speed of sound is 330 ms–1 then the frequency at which the first maximum is observed is
- 165 Hz
- 330 Hz
- 496 Hz
- 660 Hz
The correct answer is: 330 Hz
Path difference between the wave reaching at D
= 1m
For maximum 
For first maximum (n = 1) Þ
Þ 
Þ 
.
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