Physics
Grade-9
Easy
Question
Two simple pendulums of length 1 m and 16 m respectively are given small displacements at the same time in the same direction. The number of oscillations ‘N’ of the smaller pendulum for them to be in phase again is:
- 4 / 3
- 3 / 4
- 4
- 1 / 16
Hint:
The correct answer is: 4 / 3
Correct option is C)lets say they are again in phase when shorter pendulum has made n1 oscillations and bigger pendulum n2 oscillations. so total time elapsed 
they will again be in phase for the first time when the shorter pendulum has made 4 oscillations and the longer pendulum has made 1 oscillation.
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