Physics-
General
Easy

Question

Two vectors stack A with rightwards arrow on top and stack B with rightwards arrow on top are inclined at an angle theta. Now if the vectors are interchanged then the resultant turns through an angle beta. Which of the following relation is true

  1. tan invisible function application fraction numerator alpha over denominator 2 end fraction equals open parentheses fraction numerator A minus B over denominator A plus B end fraction close parentheses to the power of 2 end exponent tan invisible function application fraction numerator theta over denominator 2 end fraction  
  2. tan invisible function application fraction numerator alpha over denominator 2 end fraction equals open parentheses fraction numerator A minus B over denominator A plus B end fraction close parentheses tan invisible function application fraction numerator theta over denominator 2 end fraction  
  3. tan invisible function application fraction numerator alpha over denominator 2 end fraction equals open parentheses fraction numerator A minus B over denominator A plus B end fraction close parentheses to the power of 2 end exponent cot invisible function application fraction numerator theta over denominator 2 end fraction  
  4. tan invisible function application fraction numerator alpha over denominator 2 end fraction equals open parentheses fraction numerator A minus B over denominator A plus B end fraction close parentheses cot invisible function application fraction numerator theta over denominator 2 end fraction  

The correct answer is: tan invisible function application fraction numerator alpha over denominator 2 end fraction equals open parentheses fraction numerator A minus B over denominator A plus B end fraction close parentheses tan invisible function application fraction numerator theta over denominator 2 end fraction


    stack A with rightwards arrow on top equals A stack A with hat on top equals B stack B with hat on top. let theta be the angle between stack A with rightwards arrow on top and stack B with rightwards arrow on top.
    As per question,
    c o s alpha equals fraction numerator open parentheses A stack A with hat on top plus B stack B with hat on top close parentheses. left parenthesis A stack B with hat on top plus B stack A with hat on top right parenthesis over denominator open vertical bar A stack A with hat on top plus B stack B with hat on top close vertical bar open vertical bar A stack B with hat on top plus B stack A with hat on top close vertical bar end fraction
    or c o s alpha equals fraction numerator 2 A B plus left parenthesis A to the power of 2 end exponent plus B to the power of 2 end exponent right parenthesis c o s theta over denominator open parentheses square root of A to the power of 2 end exponent plus B to the power of 2 end exponent plus 2 A B end root c o s theta close parentheses to the power of 2 end exponent end fraction
    or 2 A B plus open parentheses A to the power of 2 end exponent plus B to the power of 2 end exponent close parentheses c o s theta equals left parenthesis A to the power of 2 end exponent plus B to the power of 2 end exponent right parenthesis c o s alpha plus 2 A B c o s theta c o s alpha
    or 2 A B left parenthesis 1 minus c o s alpha c o s theta right parenthesis
    equals open parentheses A to the power of 2 end exponent plus B to the power of 2 end exponent close parentheses left parenthesis c o s alpha minus c o s theta right parenthesis
    o fraction numerator 2 A B over denominator A to the power of 2 end exponent plus B to the power of 2 end exponent end fraction equals fraction numerator c o s alpha minus c o s theta over denominator 1 minus c o s alpha c o s theta end fraction
    or fraction numerator 2 A B over denominator left parenthesis A to the power of 2 end exponent plus B to the power of 2 end exponent right parenthesis end fraction equals fraction numerator c o s alpha minus c o s theta over denominator 1 minus c o s alpha c o s theta end fraction
    or fraction numerator 2 A B plus left parenthesis A to the power of 2 end exponent plus B to the power of 2 end exponent right parenthesis over denominator open parentheses A to the power of 2 end exponent plus B to the power of 2 end exponent close parentheses minus A B end fraction
    equals fraction numerator open parentheses c o s alpha c o s theta close parentheses plus left parenthesis 1 minus c o s alpha c o s theta right parenthesis over denominator open parentheses 1 minus c o s alpha c o s theta close parentheses plus left parenthesis c o s alpha c o s theta right parenthesis end fraction
    or fraction numerator open parentheses A plus B close parentheses to the power of 2 end exponent over denominator open parentheses A minus B close parentheses to the power of 2 end exponent end fraction equals fraction numerator open parentheses 1 plus c o s alpha close parentheses left parenthesis 1 minus c o s theta right parenthesis over denominator open parentheses 1 plus c o s theta close parentheses left parenthesis 1 minus c o s alpha right parenthesis end fraction
    equals fraction numerator tan to the power of 2 end exponent invisible function application theta divided by 2 over denominator tan to the power of 2 end exponent invisible function application theta divided by 2 end fraction
    or tanfraction numerator alpha over denominator 2 end fraction equals open parentheses fraction numerator A minus B over denominator A plus B end fraction close parentheses tan invisible function application fraction numerator theta over denominator 2 end fraction

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