Physics-
General
Easy
Question
From the top of a tower of height 50m, a ball is thrown vertically upwards with a certain velocity. It hits the ground 10 s after it is thrown up. How much time does it take to cover a distance 
where 
and 
are two points 20m and 40m below the edge of the tower? (
)
- 2.0 s
- 1.0 s
- 0.5 s
- 0.4 s
The correct answer is: 0.4 s
Let the body be projected upwards with velocity 
from top of tower. Taking vertical downward motion of boy form top of tower to ground, we have
s
As 
,
So, 
On solving 
If 
and 
are the timings taken by the ball to reach points and respectively, then
and 
On solving, we get 
s and 
s
Time taken to cover the distance
s.
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