Question
A 10 μF capacitor and a 20μ F capacitor are connected in series across 200 V supply line. The charged capacitors are then disconnected from the line and reconnected with their positive plates together and negative plates together and no external voltage is applied. What is the potential difference across each capacitor?
- 400V
- 200V
The correct answer is:
Related Questions to study
An electron enters the space between the plates of a charged capacitor as shown. The charge density on the plate is σ Electric intensity in the space between the plates is E .A uniform magnetic field also exists in the space perpendicular to the direction of E The electron moves perpendicular to both E and B without any change in direction. The time taken by the electron to travel a distance I in the space is
An electron enters the space between the plates of a charged capacitor as shown. The charge density on the plate is σ Electric intensity in the space between the plates is E .A uniform magnetic field also exists in the space perpendicular to the direction of E The electron moves perpendicular to both E and B without any change in direction. The time taken by the electron to travel a distance I in the space is
The resonance hybrid of nitrate ion is
The resonance hybrid of nitrate ion is
Bond energy is least in the following
Bond energy is least in the following
The highest bond energy is in
The highest bond energy is in
Bond energy of C–C bond is highest in
Bond energy of C–C bond is highest in
The compound having highest dipole moment is
The compound having highest dipole moment is
From the following given statements of the order of dipolemoments.
i)
ii)
iii) 
The correct combination is
From the following given statements of the order of dipolemoments.
i)
ii)
iii)
The correct combination is
Two parallel-plate capacitors of capacitance C and 2C are connected in parallel and charged to potential difference V . The battery is then disconnected and the region between the plates of C is filled completely with a material of dielectric constant K. The common potential difference across the combination becomes
Two parallel-plate capacitors of capacitance C and 2C are connected in parallel and charged to potential difference V . The battery is then disconnected and the region between the plates of C is filled completely with a material of dielectric constant K. The common potential difference across the combination becomes
A slab of dielectric constant 
and having the same thickness as the separation between the plates is introduced so as to fill one-fourth of the capacitor as shown in the figure. The new capacitance will be
, made of two semicircular rings having linear charge densities 
and 
as shown in Figure.
and 
(Fig). Each capacitor has capacitance C.
, the electrostatic potential energy of the system is zero?
represent the electric potential at the points A, B and C respectively.
