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General
Easy

Question

A gardener buys two kinds of fertilizer. Fertilizer A contains 60 straight percent sign filler materials by weight and Fertilizer B contains 40 straight percent sign filler materials by weight. Together, the fertilizers bought by the gardener contain a total of 240 pounds of filler materials. Which equation models this relationship, where x is the number of pounds of Fertilizer A and y  is the number of pounds of Fertilizer B?

  1. 0.4 x plus 0.6 y equals 240
  2. 0.6 x plus 0.4 y equals 240
  3. 40 x plus 60 y equals 240
  4. 60 x plus 40 y equals 240

hintHint:

Hint:
  • Percentage, a relative value indicating hundredth parts of any quantity.
  • Equation with two variable represents the relation between then, means how one variable change with change in another variable.

The correct answer is: 0.6 x plus 0.4 y equals 240


    Explanation:
    • We have given Fertilizer A contains 60 straight percent sign  filler materials by weight and Fertilizer B contains 40 straight percent sign filler materials by weight. Together, the fertilizers bought by the gardener contain a total of  pounds of filler materials.
    • We have to find the equation that relates the number of pounds of fertilizer A and fertilizer B.
    • We will first calculate the number of pounds of filler material in fertilizer A and fertilizer B separately and then apply the condition and then make the equation.
    Step 1 of 1:
    The number of pounds of Fertilizer A is x  and it contains 60 straight percent sign filler material
    So,
    equals 60 over 100 cross times x
    equals 0.6 x
    Now, the number of pounds of Fertilizer B is y and it contains 40 straight percent sign filler material
    So,
    equals 40 over 100 cross times y
    equals 0.4 y
    And it is given that the total number of pounds of filler materials is 240.
    So,
    0.6 x plus 0.4 y equals 240
    Hence, Option (B) is correct.

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