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Physics-

General

Easy

Question

A particle starts SHM from the mean position. Its amplitude is and total energy E . At one instant its kinetic energy is $3 E over 4$ . Its displacement at that instant is

$\frac{a}{\sqrt{2}}$
$\frac{a}{2}$
$\frac{a}{\sqrt{(\frac{3}{2})}}$
$\frac{a}{\sqrt{3}}$

The correct answer is: $a over 2$

$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell K equals 1 half m omega squared open parentheses a squared minus y squared close parentheses end cell row cell 3 over 4 E equals 1 half m omega squared open parentheses a squared minus y squared close parentheses end cell row cell 3 over 4 open parentheses 1 half m omega squared a squared close parentheses equals 1 half m omega squared open parentheses a squared minus y squared close parentheses end cell row cell y squared equals a squared minus 3 over 4 a squared equals a squared over 4 end cell row cell not stretchy rightwards double arrow y equals a over 2 end cell end table$

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