Question
A peanut company ships its product in a carton that weighs 20 oz when empty. Twenty bags of peanuts are shipped in each carton. The acceptable weight for one bag of peanuts is between 30.5 oz and 33.5 oz, inclusive. If a carton weighs too much or too little, it is opened for inspection. Write and solve a compound inequality to determine x, the weight of cartons that are opened for inspection
The correct answer is: Hence, the compound inequality is 630 oz ≤ x ≤ 690 oz
Let’s say that the weight of each bag of peanuts is w
It is given that 30.5 oz ≤ w ≤ 33.5 oz
Weight of 20 bags of peanuts lies 20 30.5 oz ≤ 20w ≤ 20 33.5 oz
610 oz ≤ 20w ≤ 670 oz
Adding 20 oz on all sides
630 oz ≤ 20w + 20 ≤ 690 oz
20w + 20 is represented as x, the weight of cartons that are opened for inspection
So, the inequality is 630 oz ≤ x ≤ 690 oz
Final Answer:
Hence, the compound inequality is 630 oz ≤ x ≤ 690 oz
Adding 20 oz on all sides
20w + 20 is represented as x, the weight of cartons that are opened for inspection
So, the inequality is 630 oz ≤ x ≤ 690 oz
Final Answer:
Hence, the compound inequality is 630 oz ≤ x ≤ 690 oz
The compound inequality statement for the weight of inspected cartons is 630 > X > 690. Here, It can also explain like this:
¶Empty carton weight = 20 oz.
Acceptable weight range per bag of peanuts:
The lower limit is 30.5 oz.
Maximum weight = 33.5 oz
20 bags = 20 peanut bags per carton
Therefore,
The following is the lower limit for carton weight after filling:
630 oz = weight of empty carton + (20 * weight per bag) 20 + (20 * 30.5)
The maximum weight of a carton after it has been filled will be:
Empty carton weight + (20 * weight per bag) 20 + (20 * 33.5) = 690 oz
As a result, the compound inequality for the inspected cartons is: 630 > X > 690.
Related Questions to study
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Inequalities define the relationship between two non-equal values. Inequality means not being equal. In mathematics, there are five inequality symbols: greater than symbol (>), less than symbol (<), greater than or equal to a sign (≥), less than or equal to a symbol (≤), and not equivalent to a symbol (≠). Many can solve simple inequalities in math by multiplying, dividing, adding, or subtracting both sides until left with the variable.
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• Then solve the inequality by subtraction and division on all sides.
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Solve x - x > -1
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¶
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1. Reconcile every inequality. 6x−3<9. ...
2. Graph every response. The numbers that prove both inequalities are plotted. The final graph will display all the values—the values shaded on both of the first two graphs— true for both inequalities.
3. Use interval notation to write out the answer. [−3,2)
¶
Line 1: passes through (0, 1) and (-1, 5)
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Line1 and line 2 are
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Line1 and line 2 are
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Addition Property: If a<b, then a + c < b + c.
Multiplication Property: If a < b and c > 0, then ac < b c and a<b and c < 0, then ac > bc.
These properties also apply to a ≤ b, a > b, and a ≥ b.