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Easy

Question

Arrange in ascending order of magnitude : 
square root of 5 comma space cube root of 11 comma 2 times root index 6 of 3

The correct answer is: Use LCM property


    Complete step by step solution:
    Here we can write, square root of 5 equals 5 to the power of 1 half end exponent comma cube root of 11 equals 11 to the power of 1 third end exponent and 2 root index 6 of 3 equals root index 6 of 12 equals 12 to the power of 1 over 6 end exponent
    On taking the LCM of 2,3,6 we have LCM as 6.
    So,                                      not stretchy rightwards double arrow 5 to the power of 1 half end exponent equals 5 to the power of fraction numerator 1 cross times 3 over denominator 2 cross times 3 end fraction end exponent equals 5 to the power of 3 over 6 end exponent
    not stretchy rightwards double arrow open parentheses 5 cubed close parentheses to the power of 1 over 6 end exponent equals 125 to the power of 1 over 6 end exponent open parentheses Since subscript midline horizontal ellipsis invisible function application open parentheses a to the power of b close parentheses to the power of c equals a to the power of b c end exponent close parentheses
    Likewise,                            not stretchy rightwards double arrow 11 to the power of 1 third end exponent equals 11 to the power of fraction numerator 1 cross times 2 over denominator 3 cross times 2 end fraction end exponent equals 11 to the power of 2 over 6 end exponent
    not stretchy rightwards double arrow open parentheses 11 squared close parentheses to the power of 1 over 6 end exponent equals 121 to the power of 1 over 6 end exponent space of 1em open parentheses text  Since  end text open parentheses a to the power of b close parentheses to the power of c equals a to the power of b c end exponent close parentheses
    Likewise, = 12 to the power of 1 over 6 end exponent
    Now, we have ,                 125 to the power of 1 over 6 end exponent comma space 121 to the power of 1 over 6 end exponent and 12 to the power of 1 over 6 end exponent
    So, here ascending order is 12 less than 121 less than 125
    not stretchy rightwards double arrow 12 to the power of 1 over 6 end exponent less than 121 to the power of 1 over 6 end exponent less than 125 to the power of 1 over 6 end exponent
    not stretchy rightwards double arrow 12 to the power of 1 over 6 end exponent less than 11 to the power of 1 third end exponent less than 5 to the power of 1 half end exponent
    not stretchy rightwards double arrow root index 6 of 12 less than cube root of 11 less than root index blank of 5

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