Biology
General
Easy

Question

A plant of type ‘H’ will produce seeds with the genotype identical to seeds produced by the plants of

  1. Type M    
  2. Type J    
  3. Type P    
  4. Type N    

The correct answer is: Type N

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Female gametes In the Punnet square given above, the genotype of the female parents and male parents respectively.

Female gametes In the Punnet square given above, the genotype of the female parents and male parents respectively.

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Phenol  Name of the above reaction is

Phenol  Name of the above reaction is

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The product ‘A’ in the following reaction is

The product ‘A’ in the following reaction is

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Which will undergo a Friedel-Craft's alkylation reaction

Which will undergo a Friedel-Craft's alkylation reaction

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Sp. vol. of cylindrical virus particle is 6.02 cross times 10 to the power of negative 2 end exponent cc divided by gm . Whose radius and length are 7 text Å  end text straight & 10 text Å end text respectively. If straight N subscript straight A equals 6.02 cross times 10 to the power of 23. Find mol. wt. of uirus -

Sp. vol. of cylindrical virus particle is 6.02 cross times 10 to the power of negative 2 end exponent cc divided by gm . Whose radius and length are 7 text Å  end text straight & 10 text Å end text respectively. If straight N subscript straight A equals 6.02 cross times 10 to the power of 23. Find mol. wt. of uirus -

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H O 

H O 

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Which of the following reaction is correctly represented

Which of the following reaction is correctly represented

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A 0.200 M KOH solutions is electrolyzed for 1.5 h using a current of 8.00 A How many moles of O2 were produced at the anode?

A 0.200 M KOH solutions is electrolyzed for 1.5 h using a current of 8.00 A How many moles of O2 were produced at the anode?

chemistry-General
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Electrolysis involves electronation and de-electronation at the respective electrodes Anode of electrolytic cell is the electrode at which de-electronation takes place whereas at cathode electronation is noticed If two or more ions of same charge are to be electonated or de electronated, the ion having laser discharge potential is discharged Discharge potential of anion refers for E0OP of E0RP as the case may be The products formed at either electrode is given in terms of Faraday's laws of electrolysis i.e. w equals fraction numerator blank E i t blank over denominator 96500 end fraction During electrolysis of CuSO4(aq), the pH of solution becomes

Electrolysis involves electronation and de-electronation at the respective electrodes Anode of electrolytic cell is the electrode at which de-electronation takes place whereas at cathode electronation is noticed If two or more ions of same charge are to be electonated or de electronated, the ion having laser discharge potential is discharged Discharge potential of anion refers for E0OP of E0RP as the case may be The products formed at either electrode is given in terms of Faraday's laws of electrolysis i.e. w equals fraction numerator blank E i t blank over denominator 96500 end fraction During electrolysis of CuSO4(aq), the pH of solution becomes

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Conductors allow the passage of electric current through them Metallic and electrolytic are the two types of conductors Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively Specific conductance of conductivity of the electrolyte solution is given by the following relation :
logical and subscript m end subscript equals K x fraction numerator 1000 over denominator M end fraction logical and subscript e end subscript equals K x fraction numerator 1000 over denominator blank N end fraction where, M and N are the molarity and normality of the solution respectively. Molar conductance of storage electrolyte depends on concentration : logical and subscript m end subscript equals logical and subscript m end subscript superscript 0 end superscript minus b square root of c where, logical and subscript m end subscript superscript 0 end superscript equals molar conductance at infinite dilution
c= concentration of the solution b= constant
The degrees of dissociation of weak electrolytes are calculated as: alpha equals fraction numerator logical and subscript m end subscript over denominator logical and subscript m end subscript superscript 0 end superscript end fraction equals fraction numerator logical and subscript e end subscript over denominator logical and subscript e end subscript superscript 0 end superscript end fraction
For which of the following electrolytic solution logical and subscript m and logical and subscript e are equal ?

Conductors allow the passage of electric current through them Metallic and electrolytic are the two types of conductors Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively Specific conductance of conductivity of the electrolyte solution is given by the following relation :
logical and subscript m end subscript equals K x fraction numerator 1000 over denominator M end fraction logical and subscript e end subscript equals K x fraction numerator 1000 over denominator blank N end fraction where, M and N are the molarity and normality of the solution respectively. Molar conductance of storage electrolyte depends on concentration : logical and subscript m end subscript equals logical and subscript m end subscript superscript 0 end superscript minus b square root of c where, logical and subscript m end subscript superscript 0 end superscript equals molar conductance at infinite dilution
c= concentration of the solution b= constant
The degrees of dissociation of weak electrolytes are calculated as: alpha equals fraction numerator logical and subscript m end subscript over denominator logical and subscript m end subscript superscript 0 end superscript end fraction equals fraction numerator logical and subscript e end subscript over denominator logical and subscript e end subscript superscript 0 end superscript end fraction
For which of the following electrolytic solution logical and subscript m and logical and subscript e are equal ?

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 A Galvanic cell consists of three compartments as shown in figure The first compartment contains ZnSO4 (1M) and III compartment contains CuSO4 (1M) The mid compartment contain NaNO3(M) Each compartment contains 1L solution:E subscript Z n to the power of 2 plus end exponent divided by Z n end subscript superscript o end superscript equals negative 0.76 semicolon E subscript C u to the power of 2 plus end exponent divided by C u end subscript superscript o end superscript equals plus 0.34
The concentration of S O subscript 4 end subscript superscript 2 minus end superscript ion in III compartment after discharge of 0.1 F charge will be :

 A Galvanic cell consists of three compartments as shown in figure The first compartment contains ZnSO4 (1M) and III compartment contains CuSO4 (1M) The mid compartment contain NaNO3(M) Each compartment contains 1L solution:E subscript Z n to the power of 2 plus end exponent divided by Z n end subscript superscript o end superscript equals negative 0.76 semicolon E subscript C u to the power of 2 plus end exponent divided by C u end subscript superscript o end superscript equals plus 0.34
The concentration of S O subscript 4 end subscript superscript 2 minus end superscript ion in III compartment after discharge of 0.1 F charge will be :

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 A Galvanic cell consists of three compartments as shown in figure The first compartment contains ZnSO4 (1M) and III compartment contains CuSO4 (1M) The mid compartment contain NaNO3(M) Each compartment contains 1L solution:E subscript Z n to the power of 2 plus end exponent divided by Z n end subscript superscript o end superscript equals negative 0.76 semicolon E subscript C u to the power of 2 plus end exponent divided by C u end subscript superscript o end superscript equals plus 0.34
The concentration of N O subscript 3 end subscript superscript minus end superscript in mid compartment after discharge of 0.1F of charge will be:

 A Galvanic cell consists of three compartments as shown in figure The first compartment contains ZnSO4 (1M) and III compartment contains CuSO4 (1M) The mid compartment contain NaNO3(M) Each compartment contains 1L solution:E subscript Z n to the power of 2 plus end exponent divided by Z n end subscript superscript o end superscript equals negative 0.76 semicolon E subscript C u to the power of 2 plus end exponent divided by C u end subscript superscript o end superscript equals plus 0.34
The concentration of N O subscript 3 end subscript superscript minus end superscript in mid compartment after discharge of 0.1F of charge will be:

chemistry-General
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General
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 A Galvanic cell consists of three compartments as shown in figure The first compartment contains ZnSO4 (1M) and III compartment contains CuSO4 (1M) The mid compartment contain NaNO3(M) Each compartment contains 1L solution:E subscript Z n to the power of 2 plus end exponent divided by Z n end subscript superscript o end superscript equals negative 0.76 semicolon E subscript C u to the power of 2 plus end exponent divided by C u end subscript superscript o end superscript equals plus 0.34
The concentration of Zn+2 in first compartment after discharge of 0.1 F charge will be :

 A Galvanic cell consists of three compartments as shown in figure The first compartment contains ZnSO4 (1M) and III compartment contains CuSO4 (1M) The mid compartment contain NaNO3(M) Each compartment contains 1L solution:E subscript Z n to the power of 2 plus end exponent divided by Z n end subscript superscript o end superscript equals negative 0.76 semicolon E subscript C u to the power of 2 plus end exponent divided by C u end subscript superscript o end superscript equals plus 0.34
The concentration of Zn+2 in first compartment after discharge of 0.1 F charge will be :

chemistry-General
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Which one of the following reactions would produce secondary alcohol

Which one of the following reactions would produce secondary alcohol

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 A and B respectively are

 A and B respectively are

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