Maths-
General
Easy

Question

Lt subscript x not stretchy rightwards arrow 0 end subscript invisible function application x squared space cos invisible function application 2 over x

  1. does not exit
  2. none of these

The correct answer is:


    limit as x rightwards arrow 0 of open parentheses x squared cos 2 over x close parentheses
W e space k n o w space t h a t comma
cos x element of open parentheses negative 1 comma 1 close parentheses
T h e r e f o r e comma
minus 1 less or equal than cos 2 over x less or equal than 1
minus x squared f open parentheses x close parentheses less or equal than x squared cos 2 over x less or equal than x squared f open parentheses x close parentheses
F o r space x rightwards arrow 0 comma
0 less or equal than limit as x rightwards arrow 0 of open parentheses x squared cos 2 over x close parentheses less or equal than 0

H e n c e comma space limit as x rightwards arrow 0 of open parentheses x squared cos 2 over x close parentheses equals 0

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