Grignard reagent adds to

A wire carrying a current of 4A is bent in the form of a parabola as shown in figure, where x and y are in meter. The wire is placed in a uniform magnetic field tesla. The force acting on the wire is

An infinitely long straight wire is bent as shown in figure. The circular portion has a radius of 10 cm with its center O at a distance r from the straight part. The value of r such that the magnetic field at the center O of the circular portion is zero will be :-

Two cylindrical straight and very long nonmagnetic conductors A and B, insulated from each other, carry a current I in the positive and the negative z–direction respectively. The direction of magnetic field at origin is

Current i = 2.5 A flows along the circle (here x & y in cm) as shown. Magnetic field at point (0, 0, 4 cm) is

There are constant electric field & magnetic field present between plates P and . A particle of mass m is projected from plate P' along y axis with velocity v₁ . After moving on the curved path, it passes through point A just grazing the plate P with velocity v₂ . The magnitude of impulse(i.e. )provided by magnetic force during the motion of particle from origin to point A is :–

In a set of reactions, acetic acid yields a product [C].

In a set of reactions, m-bromo benzoic acid gave a product ‘D’. Identify the product.

 Compound C in the above reaction is

Compounds of general formula are called

The liquid in the watch glass in the following figure is :-

we can summarize the sum of GP formulas as follows:

• S∞ = a / (1 - r) when |r| < 1
• S∞ = ±∞, when |r| ≥ 1

 The IUPAC name of ‘B’ is

Match the reactant in Column-I with the reaction in Column-II

A semi circular current carrying wire having radius R is placed in plane with its centre at origin 'O'. There is non–uniform magnetic field (here B0 is +ve constant) is existing in the region. The magnetic force acting on semicircular wire will be along

A particle moving with velocity v having specific charge (q/m) enters a region of magnetic field B having width at angle to the boundary of magnetic field. Find the angle in the diagram.