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Chemistry-

General

Easy

Question

In body-centered cubic lattice given below, the three distances AB, AC, and AA'' are

$a, \sqrt{2} a, \frac{\sqrt{3} a}{2}$
$a, \frac{\sqrt{3} a}{2}, \sqrt{2} a$
$\frac{\sqrt{3} a}{2}, \sqrt{2} a, a$
$a, \frac{a}{\sqrt{2}}, \frac{\sqrt{3} a}{2}$

The correct answer is: $a comma square root of 2 a comma fraction numerator square root of 3 a over denominator 2 end fraction$

1. Edge length $equals blank A B equals A D equals B C equals C D equals a$
2. $A C equals square root of 2 a$
3. $A G$ (body diagonal) $equals square root of 3 a$
Therefore $A A to the power of ´ end exponent equals A G divided by 2 equals fraction numerator square root of 3 over denominator 2 end fraction a$

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The packing efficiency of the two-dimensional square unit cell shown below is

The packing efficiency of the two-dimensional square unit cell shown below is

chemistry-General

A particle A of mass $fraction numerator 10 over denominator 7 end fraction blank$ kg is moving in the positive direction of x. Its initial position is x = 0 & initial velocity is 1 $m divided by s$ . The velocity at x = 10 is in $m divided by s$ (use the graph given)

A particle A of mass $fraction numerator 10 over denominator 7 end fraction blank$ kg is moving in the positive direction of x. Its initial position is x = 0 & initial velocity is 1 $m divided by s$ . The velocity at x = 10 is in $m divided by s$ (use the graph given)

physics-General

STATEMENT-1 : A block of mass m is placed at rest on rough horizontal surface. The coefficient of friction between the block and horizontal surface is $mu equals 1 divided by 3$ . The minimum force F applied at angle $theta equals 37 to the power of ring operator end exponent$ (as shown in figure) to pull the block horizontally is not equal to mmg. (Take $s i n invisible function application 37 to the power of ring operator end exponent equals 5 divided by 3 comma c o s invisible function application 37 to the power of ring operator end exponent equals 5 divided by 4$ )

STATEMENT-2 : For a block of mass m placed on rough horizontal surface, the minimum horizontal force required to pull the block is $mu m g$ . The minimum force F applied at angle $theta$ (as shown in figure) to pull the block horizontally may be less than mmg. (Where $mu$ is co-efficient of friction)

STATEMENT-1 : A block of mass m is placed at rest on rough horizontal surface. The coefficient of friction between the block and horizontal surface is $mu equals 1 divided by 3$ . The minimum force F applied at angle $theta equals 37 to the power of ring operator end exponent$ (as shown in figure) to pull the block horizontally is not equal to mmg. (Take $s i n invisible function application 37 to the power of ring operator end exponent equals 5 divided by 3 comma c o s invisible function application 37 to the power of ring operator end exponent equals 5 divided by 4$ )

STATEMENT-2 : For a block of mass m placed on rough horizontal surface, the minimum horizontal force required to pull the block is $mu m g$ . The minimum force F applied at angle $theta$ (as shown in figure) to pull the block horizontally may be less than mmg. (Where $mu$ is co-efficient of friction)

physics-General

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In the following figure, find the direction of friction on the blocks and ground respectively

In the following figure, find the direction of friction on the blocks and ground respectively

physics-General

A mass m is supported as shown in the figure by ideal strings connected to a rigid wall and to a mass 3m at rest on a fixed horizontal surface. The string connected to larger mass is horizontal, that connected to smaller mass is vertical and the one connected to wall makes an angle $60 to the power of ring operator end exponent$ with horizontal. Then the minimum coefficient of static friction between the larger mass and the horizontal surface that permits the system to remain in equilibrium in the situation shown is:

A mass m is supported as shown in the figure by ideal strings connected to a rigid wall and to a mass 3m at rest on a fixed horizontal surface. The string connected to larger mass is horizontal, that connected to smaller mass is vertical and the one connected to wall makes an angle $60 to the power of ring operator end exponent$ with horizontal. Then the minimum coefficient of static friction between the larger mass and the horizontal surface that permits the system to remain in equilibrium in the situation shown is:

physics-General

Given $m subscript A end subscript equals 20 k g comma m subscript B end subscript equals 10 k g comma m subscript C end subscript equals 20 k g$ . Between A and B $mu subscript 1 end subscript equals 0.3$ , between B and C $mu subscript 2 end subscript equals 0.3$ and between C and ground $mu subscript 3 end subscript equals 0.1$ . The least horizontal force F to start the motion of any part of the system of three blocks resting upon one another as shown in figure is (g = 10 $m divided by s to the power of 2 end exponent$ )

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physics-General

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What are types of following semiconductors I and II

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chemistry-General

A force F = t is applied to a block A as shown in figure, where t is time in seconds. The force is applied at t = 0 seconds when the system was at rest. Which of the following graph correctly gives the frictional force between A and horizontal surface as a function of time t.[Assume that at t = 0, tension in the string connecting the two blocks is zero]

A force F = t is applied to a block A as shown in figure, where t is time in seconds. The force is applied at t = 0 seconds when the system was at rest. Which of the following graph correctly gives the frictional force between A and horizontal surface as a function of time t.[Assume that at t = 0, tension in the string connecting the two blocks is zero]

physics-General

The two blocks, m = 10 kg and M = 50 kg are free to move as shown. The coefficient of static friction between the blocks is 0.5 and there is no friction between M and the ground. A minimum horizontal force F is applied to hold m against M that is equal to :

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A bead of mass m is located on a parabolic wire with its axis vertical and vertex directed towards downward as in figure and whose equation is $x to the power of 2 end exponent equals a y$ . If the coefficient of friction is $mu$ , the highest distance above the x-axis at which the particle will be in equilibrium is

A bead of mass m is located on a parabolic wire with its axis vertical and vertex directed towards downward as in figure and whose equation is $x to the power of 2 end exponent equals a y$ . If the coefficient of friction is $mu$ , the highest distance above the x-axis at which the particle will be in equilibrium is

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