Question
(Me)2SiCl2 on hydrolysis will produce -
The correct answer is:
Silicone
Related Questions to study
The coefficient of 
in 
is
The coefficient of in is
(Me)2SiCl2 on hydrolysis will produce -
(Me)2SiCl2 on hydrolysis will produce -
An elastic string of unstretched length and force constant is stretched by a small length . It is further stretched by another small length . The work done in the second stretching is
An elastic string of unstretched length and force constant is stretched by a small length . It is further stretched by another small length . The work done in the second stretching is
A shell of mass moving with velocity suddenly breaks into 2 pieces. The part having mass remains stationary. The velocity of the other shell will be
A shell of mass moving with velocity suddenly breaks into 2 pieces. The part having mass remains stationary. The velocity of the other shell will be
If 
then B=
If then B=
The set S : = { 1, 2, 3 .........12} is to be partitioned into three sets A, B, C of equal size. Thus A 
B C = S, A 
B = B C = A C = 
. The number of ways to partition S is -
The set S : = { 1, 2, 3 .........12} is to be partitioned into three sets A, B, C of equal size. Thus A B C = S, A B = B C = A C = . The number of ways to partition S is -
A one kilowatt motor is used to pump water from a well 10 m deep. The quantity of water pumped out per second is nearly
A one kilowatt motor is used to pump water from a well 10 m deep. The quantity of water pumped out per second is nearly
Assertion (A) : The Remainder obtained when the polynomial 
is divided by 
Is 1
Reason (R): If 
is divided by 
then the remainder is f(a)
Assertion (A) : The Remainder obtained when the polynomial is divided by Is 1
Reason (R): If is divided by then the remainder is f(a)
A ball hits the floor and rebounds after inelastic collision. In this case
A ball hits the floor and rebounds after inelastic collision. In this case
Statement I Two particles moving in the same direction do not lose all their energy in a completely inelastic collision.
Statement II Principle of conservation of momentum holds true for all kinds of collisions.
Statement I Two particles moving in the same direction do not lose all their energy in a completely inelastic collision.
Statement II Principle of conservation of momentum holds true for all kinds of collisions.
A mass M is lowered with the help of a string by a distance h at a constant acceleration g/2. The work done by the string will be
A mass M is lowered with the help of a string by a distance h at a constant acceleration g/2. The work done by the string will be
A particle begins at the origin and moves successively in the following manner as shown, 1 unit to the right, 1/2 unit up, 1/4 unit to the right, 1/8 unit down, 1/16 unit to the right etc. The length of each move is half the length of the previous move and movement continues in the ‘zigzag’ manner indefinitely. The co-ordinates of the point to which the ‘zigzag’ converges is –
A particle begins at the origin and moves successively in the following manner as shown, 1 unit to the right, 1/2 unit up, 1/4 unit to the right, 1/8 unit down, 1/16 unit to the right etc. The length of each move is half the length of the previous move and movement continues in the ‘zigzag’ manner indefinitely. The co-ordinates of the point to which the ‘zigzag’ converges is –
The greatest possible number of points of intersections of 8 straight line and 4 circles is :
The students can make an error if they don’t know about the formula for calculating the number of points as mentioned in the hint which is as follows
The number point of intersection between two lines can be counted by finding the number of ways in which two lines can be selected out of the lot as two lines can intersect at most one point.
The number point of intersection between two circles can be counted by finding the number of ways in which two circles can be selected out of the lot multiplied by 2 as two circles can intersect at most two points.
The number point of intersection between two circles can be counted by finding the number of ways in which one circle and one line can be selected out of the lot multiplied by 2 as one circle and one line can intersect at most two points.
The greatest possible number of points of intersections of 8 straight line and 4 circles is :
The students can make an error if they don’t know about the formula for calculating the number of points as mentioned in the hint which is as follows
The number point of intersection between two lines can be counted by finding the number of ways in which two lines can be selected out of the lot as two lines can intersect at most one point.
The number point of intersection between two circles can be counted by finding the number of ways in which two circles can be selected out of the lot multiplied by 2 as two circles can intersect at most two points.
The number point of intersection between two circles can be counted by finding the number of ways in which one circle and one line can be selected out of the lot multiplied by 2 as one circle and one line can intersect at most two points.
,then A
