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Chemistry-

General

Easy

Question

One cationic complex has two isomers A and B Each has one $C o to the power of 3 plus end exponent$ five $N H subscript 3 end subscript$ ,one $B r to the power of minus end exponent$ and one $S O subscript 4 end subscript superscript 2 minus end superscript$ stoichiometrically A gives white ppt with $B a C l subscript 2 end subscript$ while B give yellow ppt with $A g N 0 subscript 3 end subscript$ A can be:

$[C o {({N H}_{3})}_{5}] {B r S O}_{4}$
$[C o {({N H}_{3})}_{5} {S O}_{4}] B r$
$[C o {({N H}_{3})}_{5} B r] {S O}_{4}$
$[C o {({N H}_{3})}_{4} {S O}_{4}] B r \cdot {N H}_{3}$

The correct answer is: $open square brackets C o open parentheses N H subscript 3 end subscript close parentheses subscript 5 end subscript B r close square brackets S O subscript 4 end subscript$

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