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Chemistry-

General

Easy

Question

The functional groups of (B) and (C) respectively are-

$- C N, - N H -$

The correct answer is: $negative C N comma negative N H minus$

Related Questions to study

C and D in the sequence are -

C and D in the sequence are -

chemistry-General

Compound is a

Compound is a

chemistry-General

The diagram (figure) shows a venturimeter, through which water is flowing. The speed of water at X is 2 cm/s. The speed of water at Y (taking g = 1000 $c m divided by s to the power of 2 end exponent$ ) is :–

The diagram (figure) shows a venturimeter, through which water is flowing. The speed of water at X is 2 cm/s. The speed of water at Y (taking g = 1000 $c m divided by s to the power of 2 end exponent$ ) is :–

physics-General

parallel

In the figure below is shown the flow of liquid through a horizontal pipe. Three tubes A, B and C are connected to the pipe. The radii of the tubes, A, B and C at the junction are respectively 2 cm, 1 cm. and 2 cm. It can be said that the

In the figure below is shown the flow of liquid through a horizontal pipe. Three tubes A, B and C are connected to the pipe. The radii of the tubes, A, B and C at the junction are respectively 2 cm, 1 cm. and 2 cm. It can be said that the

physics-General

A body floats in a liquid contained in a beaker. The whole system is shown in figure falling under gravity. The up thrust on the body due to liquid is :–

A body floats in a liquid contained in a beaker. The whole system is shown in figure falling under gravity. The up thrust on the body due to liquid is :–

physics-General

Two vessels A and B have the same base area and contain water to the same height, but the mass of water in A is four times that in B. The ratio of the liquid thrust at the base of A to that at the base of B is :–

Two vessels A and B have the same base area and contain water to the same height, but the mass of water in A is four times that in B. The ratio of the liquid thrust at the base of A to that at the base of B is :–

physics-General

parallel

The differential coefficient of $f left parenthesis log invisible function application x right parenthesis comma text where end text f left parenthesis x right parenthesis equals log invisible function application x$ is

The differential coefficient of $f left parenthesis log invisible function application x right parenthesis comma text where end text f left parenthesis x right parenthesis equals log invisible function application x$ is

Let $f left parenthesis x right parenthesis equals e to the power of x comma g left parenthesis x right parenthesis equals sin to the power of negative 1 end exponent invisible function application x text and end text h left parenthesis x right parenthesis equals f left square bracket g left parenthesis x right parenthesis right square bracket comma text then end text fraction numerator h to the power of straight prime left parenthesis x right parenthesis over denominator h left parenthesis x right parenthesis end fraction$ is equal to

Let $f left parenthesis x right parenthesis equals e to the power of x comma g left parenthesis x right parenthesis equals sin to the power of negative 1 end exponent invisible function application x text and end text h left parenthesis x right parenthesis equals f left square bracket g left parenthesis x right parenthesis right square bracket comma text then end text fraction numerator h to the power of straight prime left parenthesis x right parenthesis over denominator h left parenthesis x right parenthesis end fraction$ is equal to

If $f left parenthesis x right parenthesis equals fraction numerator g left parenthesis x right parenthesis plus g left parenthesis negative x right parenthesis over denominator 2 end fraction plus fraction numerator 2 over denominator left ceiling h left parenthesis x right parenthesis plus h left parenthesis negative x right parenthesis right square bracket to the power of negative 1 end exponent end fraction$ where g and are differentiable function, then $f to the power of straight prime left parenthesis 0 right parenthesis$ is

If $f left parenthesis x right parenthesis equals fraction numerator g left parenthesis x right parenthesis plus g left parenthesis negative x right parenthesis over denominator 2 end fraction plus fraction numerator 2 over denominator left ceiling h left parenthesis x right parenthesis plus h left parenthesis negative x right parenthesis right square bracket to the power of negative 1 end exponent end fraction$ where g and are differentiable function, then $f to the power of straight prime left parenthesis 0 right parenthesis$ is

parallel

If $f left parenthesis x right parenthesis$ and $straight g left parenthesis straight x right parenthesis$ are two functions with $g left parenthesis x right parenthesis equals x minus 1 over x text and fog end text left parenthesis x right parenthesis equals x cubed minus 1 over x cubed text , then end text f to the power of straight prime left parenthesis x right parenthesis text is end text$

If $f left parenthesis x right parenthesis$ and $straight g left parenthesis straight x right parenthesis$ are two functions with $g left parenthesis x right parenthesis equals x minus 1 over x text and fog end text left parenthesis x right parenthesis equals x cubed minus 1 over x cubed text , then end text f to the power of straight prime left parenthesis x right parenthesis text is end text$

$fraction numerator d over denominator d x end fraction sin to the power of negative 1 end exponent invisible function application open parentheses x square root of 1 minus x end root plus square root of x square root of open 1 minus x squared close parentheses end root close$ is equal to

$fraction numerator d over denominator d x end fraction sin to the power of negative 1 end exponent invisible function application open parentheses x square root of 1 minus x end root plus square root of x square root of open 1 minus x squared close parentheses end root close$ is equal to

If $y equals tan to the power of negative 1 end exponent invisible function application left parenthesis sec invisible function application x minus tan invisible function application x right parenthesis$ , then $fraction numerator d y over denominator d x end fraction$ is

If $y equals tan to the power of negative 1 end exponent invisible function application left parenthesis sec invisible function application x minus tan invisible function application x right parenthesis$ , then $fraction numerator d y over denominator d x end fraction$ is

parallel

If $f left parenthesis x right parenthesis equals fraction numerator x minus 1 over denominator 4 end fraction plus fraction numerator left parenthesis x minus 1 right parenthesis cubed over denominator 12 end fraction plus fraction numerator left parenthesis x minus 1 right parenthesis to the power of 5 over denominator 20 end fraction plus fraction numerator left parenthesis x minus 1 right parenthesis to the power of 7 over denominator 28 end fraction plus midline horizontal ellipsis comma text where end text 0 less than x less than 2 comma text then end text f to the power of straight prime left parenthesis x right parenthesis text is equal to end text$

If $f left parenthesis x right parenthesis equals fraction numerator x minus 1 over denominator 4 end fraction plus fraction numerator left parenthesis x minus 1 right parenthesis cubed over denominator 12 end fraction plus fraction numerator left parenthesis x minus 1 right parenthesis to the power of 5 over denominator 20 end fraction plus fraction numerator left parenthesis x minus 1 right parenthesis to the power of 7 over denominator 28 end fraction plus midline horizontal ellipsis comma text where end text 0 less than x less than 2 comma text then end text f to the power of straight prime left parenthesis x right parenthesis text is equal to end text$

Find $fraction numerator d y over denominator d x end fraction comma text if end text x equals 2 cos invisible function application theta minus cos invisible function application 2 theta text and end text y equals 2 sin invisible function application theta minus sin invisible function application 2 theta$

Find $fraction numerator d y over denominator d x end fraction comma text if end text x equals 2 cos invisible function application theta minus cos invisible function application 2 theta text and end text y equals 2 sin invisible function application theta minus sin invisible function application 2 theta$

Variation of internal energy with density of one mole of monatomic gas is depicted in the adjoining figure, corresponding variation of pressure with volume can be depicted as (Assuming the curve is rectangular hyperbola)

Variation of internal energy with density of one mole of monatomic gas is depicted in the adjoining figure, corresponding variation of pressure with volume can be depicted as (Assuming the curve is rectangular hyperbola)

Physics-General

parallel

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