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Chemistry-

General

Easy

Question

The hybridization of orbitals of Na to min $N O subscript 3 end subscript superscript minus end superscript$ $N O subscript 2 end subscript superscript plus end superscript comma$ and $N H subscript 4 end subscript superscript plus end superscript$ are respectively

$s p, s p^{2}, and s p^{3}$
$s p^{2}, s p and s p^{3}$
$s p, s p^{3}, and s p^{2}$
$s p^{2}, s p^{3}, and s p$

The correct answer is: $s p to the power of 2 end exponent comma s p text and end text s p to the power of 3 end exponent$

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