Chemistry-
General
Easy

Question

The IUPAC name for

  1. Ortho hydroxy methyl phenol    
  2. 2-Hydroxy benzy1 alcohol    
  3. Salicyl alcohol    
  4. 2-Hydroxy methyl phenol    

The correct answer is: Salicyl alcohol

Related Questions to study

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The IUPAC name of the given compound is -

The IUPAC name of the given compound is -

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What will be the order of reactivity of the following alcohols towards concentrated HCI ?
I) 
II) 
III) 
IV) 

What will be the order of reactivity of the following alcohols towards concentrated HCI ?
I) 
II) 
III) 
IV) 

chemistry-General
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The major product formed in the reaction is

The major product formed in the reaction is

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In the given reaction

In the given reaction

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In the following hydration the major alcohol product formed is -

In the following hydration the major alcohol product formed is -

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A tertiary alcohol is obtained when C H subscript 3 end subscript M g I reacts with-

A tertiary alcohol is obtained when C H subscript 3 end subscript M g I reacts with-

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General
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The missing structures A and B in the reaction sequence:
; A&B are given by the set -

The missing structures A and B in the reaction sequence:
; A&B are given by the set -

chemistry-General
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In the reaction,  the product obtained will be -

In the reaction,  the product obtained will be -

chemistry-General
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One litre of a gas collected at NTP will occupy at 2 atmospheric. pressure and 27 to the power of 0 C:

One litre of a gas collected at NTP will occupy at 2 atmospheric. pressure and 27 to the power of 0 C:

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General
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blank subscript 83 end subscript superscript 214 end superscript B i stack ⟶ with alpha text -emission  end text on top A stack ⟶ with beta text -emission  end text on top B stack ⟶ with beta minus text  cmission  end text on top C stack ⟶ with beta text -emission  end text on top D stack ⟶ with alpha text -emission  end text on top E E' is.an element of stable nucleus What is the element 'E'?

blank subscript 83 end subscript superscript 214 end superscript B i stack ⟶ with alpha text -emission  end text on top A stack ⟶ with beta text -emission  end text on top B stack ⟶ with beta minus text  cmission  end text on top C stack ⟶ with beta text -emission  end text on top D stack ⟶ with alpha text -emission  end text on top E E' is.an element of stable nucleus What is the element 'E'?

chemistry-General
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Consider the following nuclear reactions: table row cell blank subscript 92 end subscript superscript 238 end superscript M ⟶ blank subscript y end subscript superscript x end superscript N plus 2 blank subscript 2 end subscript superscript 4 end superscript H e end cell row cell blank subscript y end subscript superscript x end superscript N ⟶ blank subscript B end subscript superscript A end superscript L plus 2 beta to the power of plus end exponent end cell end table the number of neutrons present in the element 'L' is:

Consider the following nuclear reactions: table row cell blank subscript 92 end subscript superscript 238 end superscript M ⟶ blank subscript y end subscript superscript x end superscript N plus 2 blank subscript 2 end subscript superscript 4 end superscript H e end cell row cell blank subscript y end subscript superscript x end superscript N ⟶ blank subscript B end subscript superscript A end superscript L plus 2 beta to the power of plus end exponent end cell end table the number of neutrons present in the element 'L' is:

chemistry-General
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A radioactive element decays by parallel path as given below :
table attributes columnalign right end attributes row cell A stack ⟶ with lambda subscript 1 end subscript on top B lambda subscript 1 end subscript end cell cell blank equals 1.8 cross times 10 to the power of negative 2 end exponent s e c to the power of negative 1 end exponent end cell row cell 2 A stack ⟶ with lambda subscript 2 end subscript on top B lambda subscript 2 end subscript end cell cell blank equals 10 to the power of negative 3 end exponent s e c to the power of negative 1 end exponent end cell end table
Average life of radio nuclide a will be :

A radioactive element decays by parallel path as given below :
table attributes columnalign right end attributes row cell A stack ⟶ with lambda subscript 1 end subscript on top B lambda subscript 1 end subscript end cell cell blank equals 1.8 cross times 10 to the power of negative 2 end exponent s e c to the power of negative 1 end exponent end cell row cell 2 A stack ⟶ with lambda subscript 2 end subscript on top B lambda subscript 2 end subscript end cell cell blank equals 10 to the power of negative 3 end exponent s e c to the power of negative 1 end exponent end cell end table
Average life of radio nuclide a will be :

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General
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In the radioactive change, blank subscript negative Z end subscript superscript A end superscript P ⟶ blank subscript z plus 1 end subscript superscript A end superscript Q ⟶ blank subscript Z minus 1 end subscript superscript A minus 4 end superscript R ⟶ blank subscript Z minus 1 end subscript superscript A minus 4 end superscript S the radiations emitted in sequence are:

In the radioactive change, blank subscript negative Z end subscript superscript A end superscript P ⟶ blank subscript z plus 1 end subscript superscript A end superscript Q ⟶ blank subscript Z minus 1 end subscript superscript A minus 4 end superscript R ⟶ blank subscript Z minus 1 end subscript superscript A minus 4 end superscript S the radiations emitted in sequence are:

chemistry-General
General
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(A) blank subscript 92 end subscript superscript 238 end superscript U left parenthesis I I I B right parenthesis stack ⟶ with negative alpha on top A stack ⟶ with negative alpha on top B stack ⟶ with negative beta on top C
(R) Element B will be of IIA grou

(A) blank subscript 92 end subscript superscript 238 end superscript U left parenthesis I I I B right parenthesis stack ⟶ with negative alpha on top A stack ⟶ with negative alpha on top B stack ⟶ with negative beta on top C
(R) Element B will be of IIA grou

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General
chemistry-

The following graph illustrates:

The following graph illustrates:

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