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Chemistry-

General

Easy

Question

The Products (A) and (B) , respectively, are:

The correct answer is:

(A) $rightwards double arrow$ HI + P reduces epoxides to alkanes

Related Questions to study

The cartesian equation of the plane passing through the line of intersection of the planes $r times left parenthesis 2 ı with not stretchy bar on top plus 3 ȷ with not stretchy bar on top plus 4 k with not stretchy bar on top right parenthesis equals 1$ and $r times left parenthesis ı with not stretchy bar on top minus ȷ with not stretchy bar on top right parenthesis plus 4 equals 0$ and perpendicular to the plane $r times left parenthesis 2 ı with not stretchy bar on top minus ȷ with not stretchy bar on top plus k with not stretchy bar on top right parenthesis plus 8 equals 0$ is

The cartesian equation of the plane passing through the line of intersection of the planes $r times left parenthesis 2 ı with not stretchy bar on top plus 3 ȷ with not stretchy bar on top plus 4 k with not stretchy bar on top right parenthesis equals 1$ and $r times left parenthesis ı with not stretchy bar on top minus ȷ with not stretchy bar on top right parenthesis plus 4 equals 0$ and perpendicular to the plane $r times left parenthesis 2 ı with not stretchy bar on top minus ȷ with not stretchy bar on top plus k with not stretchy bar on top right parenthesis plus 8 equals 0$ is

Identify(A) and (B) in the reaction:

Identify(A) and (B) in the reaction:

chemistry-General

If $f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left left columnspacing 1em end attributes row cell 1 over x squared minus 1 over x squared comma x less than 0 end cell row cell sin to the power of negative 1 end exponent left parenthesis x plus b right parenthesis comma x greater or equal than 0 end cell end table close$ then at $x equals 0 comma space f left parenthesis x right parenthesis space$ is

If $f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left left columnspacing 1em end attributes row cell 1 over x squared minus 1 over x squared comma x less than 0 end cell row cell sin to the power of negative 1 end exponent left parenthesis x plus b right parenthesis comma x greater or equal than 0 end cell end table close$ then at $x equals 0 comma space f left parenthesis x right parenthesis space$ is

parallel

In the reaction $3 Br subscript 2 plus 6 CO subscript 3 superscript 2 minus end superscript plus 3 straight H subscript 2 straight O not stretchy rightwards arrow 5 Br to the power of ⊖ plus BrO subscript 3 superscript ⊖ plus 6 HCO subscript 3 superscript ⊖$

In the reaction $3 Br subscript 2 plus 6 CO subscript 3 superscript 2 minus end superscript plus 3 straight H subscript 2 straight O not stretchy rightwards arrow 5 Br to the power of ⊖ plus BrO subscript 3 superscript ⊖ plus 6 HCO subscript 3 superscript ⊖$

chemistry-General

The product (A) formed can:

The product (A) formed can:

chemistry-General

Which of the following is the strongest oxidising agent?

Which of the following is the strongest oxidising agent?

chemistry-General

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Two circles with radii $apostrophe r subscript 1 superscript blank apostrophe text and ' end text r subscript 2 apostrophe comma r subscript 1 greater than r subscript 2 greater or equal than 2$ , touch each other externally. If $apostrophe theta apostrophe$ be the angle between the direct common tangents, then

Two circles with radii $apostrophe r subscript 1 superscript blank apostrophe text and ' end text r subscript 2 apostrophe comma r subscript 1 greater than r subscript 2 greater or equal than 2$ , touch each other externally. If $apostrophe theta apostrophe$ be the angle between the direct common tangents, then

In triangle ABC, medians AD and BE are drawn. If AD=4, $straight angle DAB equals pi divided by 6$ and $straight angle ABE equals pi divided by 3$ , then the area of the △ABC is

In triangle ABC, medians AD and BE are drawn. If AD=4, $straight angle DAB equals pi divided by 6$ and $straight angle ABE equals pi divided by 3$ , then the area of the △ABC is

Two coherent sources S₁ and S₂ are separated by a distance four times the wavelength $lambda blank$ of the source. The sources lie along y axis whereas a detector moves along + x-axis. Leaving the origin and far off points the number of points where maxima are observed is

Two coherent sources S₁ and S₂ are separated by a distance four times the wavelength $lambda blank$ of the source. The sources lie along y axis whereas a detector moves along + x-axis. Leaving the origin and far off points the number of points where maxima are observed is

physics-General

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Two coherent sources separated by distance d are radiating in phase having wavelength $lambda$ . A detector moves in a big circle around the two sources in the plane of the two sources. The angular position of n = 4 interference maxima is given as

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physics-General

A beam with wavelength l falls on a stack of partially reflecting planes with separation d. The angle $theta$ that the beam should make with the planes so that the beams reflected from successive planes may interfere constructively is (where n =1, 2, ……)

A beam with wavelength l falls on a stack of partially reflecting planes with separation d. The angle $theta$ that the beam should make with the planes so that the beams reflected from successive planes may interfere constructively is (where n =1, 2, ……)

physics-General

Two ideal slits $S subscript 1 end subscript$ and $S subscript 2 end subscript$ are at a distance d apart and illuminated by light of wavelength $lambda blank$ passing through an ideal source slit S placed on the line through $S subscript 2 end subscript$ as shown. The distance between the planes of slits and the source slit is D. A screen is held at a distance D from the plane of the slits. The minimum value of d for which there is darkness at O is

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A monochromatic beam of light falls on YDSE apparatus at some angle (say $theta$ ) as shown in figure. A thin sheet of glass is inserted in front of the lower slit $S subscript 2 end subscript.$ . The central bright fringe (path difference = 0) will be obtained

A monochromatic beam of light falls on YDSE apparatus at some angle (say $theta$ ) as shown in figure. A thin sheet of glass is inserted in front of the lower slit $S subscript 2 end subscript.$ . The central bright fringe (path difference = 0) will be obtained

physics-General

Find the sum of the infinite series $fraction numerator 1 over denominator 1.3 end fraction plus fraction numerator 1 over denominator 2.5 end fraction plus fraction numerator 1 over denominator 3.7 end fraction plus fraction numerator 1 over denominator 4.9 end fraction plus horizontal ellipsis horizontal ellipsis straight infinity$

Find the sum of the infinite series $fraction numerator 1 over denominator 1.3 end fraction plus fraction numerator 1 over denominator 2.5 end fraction plus fraction numerator 1 over denominator 3.7 end fraction plus fraction numerator 1 over denominator 4.9 end fraction plus horizontal ellipsis horizontal ellipsis straight infinity$

In the figure is shown Young’s double slit experiment. Q is the position of the first bright fringe on the right side of O. P is the 11^th fringe on the other side, as measured from Q. If the wavelength of the light used is $6000 cross times 1 0 to the power of negative 10 end exponent m$ , then $S subscript 1 end subscript B$ will be equal to

In the figure is shown Young’s double slit experiment. Q is the position of the first bright fringe on the right side of O. P is the 11^th fringe on the other side, as measured from Q. If the wavelength of the light used is $6000 cross times 1 0 to the power of negative 10 end exponent m$ , then $S subscript 1 end subscript B$ will be equal to

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parallel

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