Chemistry-
General
Easy

Question

What is the IUPAC name of compound

  1. 2 - methyl - 4 – butanamine    
  2. 4 - methyl - 2 – butanamine    
  3. 3 - methyl - 1 – butanamine    
  4. 1 - amino - 3 - methyl butane    

The correct answer is: 3 - methyl - 1 – butanamine

Related Questions to study

General
chemistry-

What will be the IUPAC name of the given compound?

What will be the IUPAC name of the given compound?

chemistry-General
General
chemistry-

IUPAC name of the following compound will be ..........

IUPAC name of the following compound will be ..........

chemistry-General
General
chemistry-

Predict the IUPAC name of

Predict the IUPAC name of

chemistry-General
parallel
General
chemistry-

What is the IUPAC name of the following compound?

What is the IUPAC name of the following compound?

chemistry-General
General
chemistry-

Which IUPAC name correctly represents the following organic molecule?

Which IUPAC name correctly represents the following organic molecule?

chemistry-General
General
chemistry-

Identify the functional groups in the following compound

Identify the functional groups in the following compound

chemistry-General
parallel
General
physics-

The figure shows the path of a positively charged particle 1 through a rectangular region of uniform electric field as shown in the figure. What is the direction of electric field and the direction of deflection of particles 2,3 and 4?

The figure shows the path of a positively charged particle 1 through a rectangular region of uniform electric field as shown in the figure. What is the direction of electric field and the direction of deflection of particles 2,3 and 4?

physics-General
General
chemistry-

The compound  The compound C is

The compound  The compound C is

chemistry-General
General
chemistry-

Toluene when refluxed with Br2 in the presence of light mainly gives

Toluene when refluxed with Br2 in the presence of light mainly gives

chemistry-General
parallel
General
chemistry-

The order of reactivities of the following alkyl halides for a SN2 reaction is

The order of reactivities of the following alkyl halides for a SN2 reaction is

chemistry-General
General
chemistry-

 The above structural formula refers to

 The above structural formula refers to

chemistry-General
General
Maths-

integral subscript 0 superscript 4   square root of 16 minus x squared end root d x equals

So here we used the concept of integrals of special function and simplified it. We can also solve it manually but it will take lot of time to come to a final answer hence we used the formula of that. The integral of the given function is integral subscript 0 superscript 4   square root of 16 minus x squared end root d x equals 4 straight pi

integral subscript 0 superscript 4   square root of 16 minus x squared end root d x equals

Maths-General

So here we used the concept of integrals of special function and simplified it. We can also solve it manually but it will take lot of time to come to a final answer hence we used the formula of that. The integral of the given function is integral subscript 0 superscript 4   square root of 16 minus x squared end root d x equals 4 straight pi

parallel
General
maths-

I f integral subscript 0 superscript 4 0   d x divided by left parenthesis 2 x plus 1 right parenthesis equals l o g a t h e n a

I f integral subscript 0 superscript 4 0   d x divided by left parenthesis 2 x plus 1 right parenthesis equals l o g a t h e n a

maths-General
General
Maths-

integral subscript 0 superscript pi divided by 4 end superscript   fraction numerator sin invisible function application x plus cos invisible function application x over denominator 9 plus 16 sin invisible function application 2 x end fraction d x equals

So here we used the concept of integrals and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the substitution method which makes the problem to solve easily. The integral of the given function is integral subscript 0 superscript pi divided by 4 end superscript   fraction numerator sin invisible function application x plus cos invisible function application x over denominator 9 plus 16 sin invisible function application 2 x end fraction d x equalsfraction numerator log space 3 over denominator 20 end fraction

integral subscript 0 superscript pi divided by 4 end superscript   fraction numerator sin invisible function application x plus cos invisible function application x over denominator 9 plus 16 sin invisible function application 2 x end fraction d x equals

Maths-General

So here we used the concept of integrals and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the substitution method which makes the problem to solve easily. The integral of the given function is integral subscript 0 superscript pi divided by 4 end superscript   fraction numerator sin invisible function application x plus cos invisible function application x over denominator 9 plus 16 sin invisible function application 2 x end fraction d x equalsfraction numerator log space 3 over denominator 20 end fraction

General
Maths-

integral subscript 0 superscript pi divided by 2 end superscript   fraction numerator 1 over denominator 4 plus 5 cos invisible function application x end fraction d x equals

So here we used the concept of integrals and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the substitution method which makes problem to solve easily. The integral of the given function is fraction numerator 1 over denominator left parenthesis 3 right parenthesis end fraction cross times log left parenthesis 1 half right parenthesis

integral subscript 0 superscript pi divided by 2 end superscript   fraction numerator 1 over denominator 4 plus 5 cos invisible function application x end fraction d x equals

Maths-General

So here we used the concept of integrals and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the substitution method which makes problem to solve easily. The integral of the given function is fraction numerator 1 over denominator left parenthesis 3 right parenthesis end fraction cross times log left parenthesis 1 half right parenthesis

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.