Question
The figure shows the path of a positively charged particle 1 through a rectangular region of uniform electric field as shown in the figure. What is the direction of electric field and the direction of deflection of particles 2,3 and 4?
- Top; down , top, down
- Top; down, down, top
- Down; top, top, down
- Down; top, down, down
The correct answer is: Top; down , top, down
The figure shows the path of a +ve charged particle (1) through a rectangular region of uniform electric field.
Since, +ve charged particle moves as a parabolic path in electric field. It means the direction of electric field is upward. The direction of deflection of particle (2) which is –ve is downward. The direction of deflection of particle (3) which is +ve is upward and direction of deflection of particle (4) is downward.
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So here we used the concept of integrals of special function and simplified it. We can also solve it manually but it will take lot of time to come to a final answer hence we used the formula of that. The integral of the given function is 
So here we used the concept of integrals of special function and simplified it. We can also solve it manually but it will take lot of time to come to a final answer hence we used the formula of that. The integral of the given function is
So here we used the concept of integrals and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the substitution method which makes the problem to solve easily. The integral of the given function is 
So here we used the concept of integrals and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the substitution method which makes the problem to solve easily. The integral of the given function is
So here we used the concept of integrals and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the substitution method which makes problem to solve easily. The integral of the given function is 
So here we used the concept of integrals and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the substitution method which makes problem to solve easily. The integral of the given function is
So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to a final answer hence we used the formula. The integral of the given function is
.
So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to a final answer hence we used the formula. The integral of the given function is.
So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the formula. The integral of the given function is 
So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the formula. The integral of the given function is
So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the formula to solve. The integral of the given function is
So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the formula to solve. The integral of the given function is
Therefore, the integration of 
is 
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Therefore, the integration of is .
So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the substitution method to solve. The integral of the given function is 
So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the substitution method to solve. The integral of the given function is
So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the special case and the formula of that. The integral of the given function is 
.
So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the special case and the formula of that. The integral of the given function is .
So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the special case and the formula of that. The integral of the given function is 
.
So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the special case and the formula of that. The integral of the given function is .
