Chemistry-
General
Easy

Question

What type of crystal defect is indicated in the diagram below?

  1. Frenkel defect    
  2. Schottky defect    
  3. Interstitial defect    
  4. Frenkel and Schottky defects    

The correct answer is: Frenkel defect

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The unit cell in a body centered cubic lattice is given in the figure Each sphere has a radius, r and the cube has a side, a What fraction of the total cube volume is empty

The unit cell in a body centered cubic lattice is given in the figure Each sphere has a radius, r and the cube has a side, a What fraction of the total cube volume is empty

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If l subscript 1 end subscript comma m subscript 1 end subscript comma n subscript 1 end subscriptand l subscript 2 end subscript comma m subscript 2 end subscript comma n subscript 2 end subscript blankare text d.c.´s end text text  of  end text stack O A with rightwards arrow on top comma stack O B with rightwards arrow on top such that  where ‘O’ is the origin, then the d.c.’s of the internal bisector of the angle  are

If l subscript 1 end subscript comma m subscript 1 end subscript comma n subscript 1 end subscriptand l subscript 2 end subscript comma m subscript 2 end subscript comma n subscript 2 end subscript blankare text d.c.´s end text text  of  end text stack O A with rightwards arrow on top comma stack O B with rightwards arrow on top such that  where ‘O’ is the origin, then the d.c.’s of the internal bisector of the angle  are

maths-General
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The area bounded by the curves is square root of vertical line x vertical line end root plus square root of vertical line y vertical line end root equals square root of a and x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent (where a greater than 0 right parenthesis is

The area bounded by the curves is square root of vertical line x vertical line end root plus square root of vertical line y vertical line end root equals square root of a and x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent (where a greater than 0 right parenthesis is

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General
chemistry-

The electronic configurations of the element A,B, and C are :given below.

The bond between and C will be:

The electronic configurations of the element A,B, and C are :given below.

The bond between and C will be:

chemistry-General
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chemistry-

The electronic configurations of the element A,B, and C are :given below.

The moleculaformulof the compound formed from Band will be:

The electronic configurations of the element A,B, and C are :given below.

The moleculaformulof the compound formed from Band will be:

chemistry-General
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chemistry-

The electronic configurations of the element A,B, and C are :given below.

Stable form of C may be represented by the formula:

The electronic configurations of the element A,B, and C are :given below.

Stable form of C may be represented by the formula:

chemistry-General
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General
chemistry-

The electronic configurations of the element A,B, and C are :given below.

Stable form of A may be represented by the formula:

The electronic configurations of the element A,B, and C are :given below.

Stable form of A may be represented by the formula:

chemistry-General
General
chemistry-

Lewis concept of covalency of an element involvesoctetrule.Lateronitwasfoundthatmanyelementsin their compounds, e.g., B e F subscript 2 end subscript comma B F subscript 3 end subscript etc. have incompleteoctetwhereasP C l subscript 5 end subscript comma S F subscript 6 end subscript et c.haveexpandedoctet. This classicaconcept also failed inpredictingthegeometryof molecules. Modem concept of covalence was pro­ posed in terms of valence bond theory. Hybridizationconcept along with valence bond theory successfullexplained the geometryofvariousmoleculesbutfailedin many molecules ThebondangleN O subscript 2 end subscript superscript plus end superscript comma N O subscript 2 end subscriptandN O subscript 2 end subscript superscript minus end superscriptare,respectively:

Lewis concept of covalency of an element involvesoctetrule.Lateronitwasfoundthatmanyelementsin their compounds, e.g., B e F subscript 2 end subscript comma B F subscript 3 end subscript etc. have incompleteoctetwhereasP C l subscript 5 end subscript comma S F subscript 6 end subscript et c.haveexpandedoctet. This classicaconcept also failed inpredictingthegeometryof molecules. Modem concept of covalence was pro­ posed in terms of valence bond theory. Hybridizationconcept along with valence bond theory successfullexplained the geometryofvariousmoleculesbutfailedin many molecules ThebondangleN O subscript 2 end subscript superscript plus end superscript comma N O subscript 2 end subscriptandN O subscript 2 end subscript superscript minus end superscriptare,respectively:

chemistry-General
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chemistry-

NO is a colorless gasandan important intermediate inthemanufactureof nitricacidby catalytic oxidationofammonia. Whichofthefollowingisaneutraloxide?</span

NO is a colorless gasandan important intermediate inthemanufactureof nitricacidby catalytic oxidationofammonia. Whichofthefollowingisaneutraloxide?</span

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General
chemistry-

NO has11 valence electrons.It is impossible for all1be paired. and hence this is an odd electron molecule,and the gas is paramagnetic. Which of the following species has the smallest N-O bond length?

NO has11 valence electrons.It is impossible for all1be paired. and hence this is an odd electron molecule,and the gas is paramagnetic. Which of the following species has the smallest N-O bond length?

chemistry-General
General
chemistry-

Many bond angles can be explained by either electronegativity or size arguments. Molecules with larger difference in electronegativity values between central and outer atoms have smaller bond ang les. As the size of outer atom increases, the angle increases. The size of central atom can also be used to determine the bond angles in the series. Which has the smallest bond angle left parenthesis X minus S minus X right parenthesis in the given molecules?

Many bond angles can be explained by either electronegativity or size arguments. Molecules with larger difference in electronegativity values between central and outer atoms have smaller bond ang les. As the size of outer atom increases, the angle increases. The size of central atom can also be used to determine the bond angles in the series. Which has the smallest bond angle left parenthesis X minus S minus X right parenthesis in the given molecules?

chemistry-General
General
chemistry-

Many bond angles can be explained by either electronegativity or size arguments. Molecules with larger difference in electronegativity values between central and outer atoms have smaller bond ang les. As the size of outer atom increases, the angle increases. The size of central atom can also be used to determine the bond angles in the series.

Consider the following hydrides and arrange them in increasing order of bond ang les:
I) N H subscript 3 end subscript
II) P H subscript 3 end subscript
III) A s H subscript 3 end subscript
IV) S b H subscript 3 end subscript

Many bond angles can be explained by either electronegativity or size arguments. Molecules with larger difference in electronegativity values between central and outer atoms have smaller bond ang les. As the size of outer atom increases, the angle increases. The size of central atom can also be used to determine the bond angles in the series.

Consider the following hydrides and arrange them in increasing order of bond ang les:
I) N H subscript 3 end subscript
II) P H subscript 3 end subscript
III) A s H subscript 3 end subscript
IV) S b H subscript 3 end subscript

chemistry-General
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General
chemistry-

Many bond angles can be explained by either electronegativity or size arguments. Molecules with larger difference in electronegativity values between central and outer atoms have smaller bond ang les. As the size of outer atom increases, the angle increases. The size of central atom can also be used to determine the bond angles in the series. Consider the following molecules:
I) H subscript 2 end subscript O
II) H subscript 2 end subscript text end text S
III) H subscript 2 end subscript S e
IV) H subscript 2 end subscript T e

Arrange these molecules in increasing order of bond angle:

Many bond angles can be explained by either electronegativity or size arguments. Molecules with larger difference in electronegativity values between central and outer atoms have smaller bond ang les. As the size of outer atom increases, the angle increases. The size of central atom can also be used to determine the bond angles in the series. Consider the following molecules:
I) H subscript 2 end subscript O
II) H subscript 2 end subscript text end text S
III) H subscript 2 end subscript S e
IV) H subscript 2 end subscript T e

Arrange these molecules in increasing order of bond angle:

chemistry-General
General
chemistry-

A) 
B) 
C) 
In the thiocyanate ion, S C N to the power of minus end exponent three resonance structures are consistent with the electron -dot method Structure A has only one negative formal charge on the nitrogen atom, the most electro negative atom in the ion. Structure B has a single negative charge on the S, which is less electronegative than N. Structure C has charges of -2 on N and +1 on S, consistent with the relative electronegativities of the atoms but with a larger charge and greater charge separation than the first.
HNCs is isostructural with:

A) 
B) 
C) 
In the thiocyanate ion, S C N to the power of minus end exponent three resonance structures are consistent with the electron -dot method Structure A has only one negative formal charge on the nitrogen atom, the most electro negative atom in the ion. Structure B has a single negative charge on the S, which is less electronegative than N. Structure C has charges of -2 on N and +1 on S, consistent with the relative electronegativities of the atoms but with a larger charge and greater charge separation than the first.
HNCs is isostructural with:

chemistry-General
General
chemistry-

A) 
B) 
C) 
In the thiocyanate ion, S C N to the power of minus end exponent three resonance structures are consistent with the electron -dot method Structure A has only one negative formal charge on the nitrogen atom, the most electro negative atom in the ion. Structure B has a single negative charge on the S, which is less electronegative than N. Structure C has charges of -2 on N and +1 on S, consistent with the relative electronegativities of the atoms but with a larger charge and greater charge separation than the first. Predict the hybridization of atom which is bonded with H in structure HNCS:

A) 
B) 
C) 
In the thiocyanate ion, S C N to the power of minus end exponent three resonance structures are consistent with the electron -dot method Structure A has only one negative formal charge on the nitrogen atom, the most electro negative atom in the ion. Structure B has a single negative charge on the S, which is less electronegative than N. Structure C has charges of -2 on N and +1 on S, consistent with the relative electronegativities of the atoms but with a larger charge and greater charge separation than the first. Predict the hybridization of atom which is bonded with H in structure HNCS:

chemistry-General
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