Chemistry-
General
Easy
Question
What will be the most probable product when compound ‘X’ is treated with two equivalents of NaOH,
The correct answer is:
Related Questions to study
chemistry-
Aniline reacts with mixed acid (conc. HNO3 and conc. H2SO4 ) at 288 K to give P (51%), Q (47%) and R (51%), Q(47%) and R (2%). The major product(s) of the following reaction sequence is/are
Aniline reacts with mixed acid (conc. HNO3 and conc. H2SO4 ) at 288 K to give P (51%), Q (47%) and R (51%), Q(47%) and R (2%). The major product(s) of the following reaction sequence is/are
chemistry-General
chemistry-
The major product of the following reaction is
The major product of the following reaction is
chemistry-General
chemistry-
In the following reaction sequences V and W are respectively :
In the following reaction sequences V and W are respectively :
chemistry-General
chemistry-
GivenKcal Kcal Kcal the heat of formation of methane in Kcal will be-
GivenKcal Kcal Kcal the heat of formation of methane in Kcal will be-
chemistry-General
maths-
A set of (2n + 1) elements is given. The no. of subsets of the set which contain atmost n elements -
A set of (2n + 1) elements is given. The no. of subsets of the set which contain atmost n elements -
maths-General
chemistry-
under Hofmann conditions will give :
under Hofmann conditions will give :
chemistry-General
chemistry-
Which step is rate determining ste
Which step is rate determining ste
chemistry-General
chemistry-
Which reagent (X) is used to convert I to II
Which reagent (X) is used to convert I to II
chemistry-General
chemistry-
An organic compound A upon reacting with NH3 gives B. On heating B gives C. C in presence of KOH reacts with Br2 to given CH3CH2NH2 . A is :
An organic compound A upon reacting with NH3 gives B. On heating B gives C. C in presence of KOH reacts with Br2 to given CH3CH2NH2 . A is :
chemistry-General
Maths-
If r, s, t are prime numbers and p, q are the positive integers such that the LCM of p, q is , then the number of ordered pair (p, q) is-
Be careful about selecting the r s and t for this particular problem. Because number ways for each selection of r, s and t there are 3 cases. Because there are two values given
p, q . Hence to calculate the total number of ways is to multiply the number of ways for r, number of ways for s and number of ways for t. So, in this way to solve this particular type of problem.
If r, s, t are prime numbers and p, q are the positive integers such that the LCM of p, q is , then the number of ordered pair (p, q) is-
Maths-General
Be careful about selecting the r s and t for this particular problem. Because number ways for each selection of r, s and t there are 3 cases. Because there are two values given
p, q . Hence to calculate the total number of ways is to multiply the number of ways for r, number of ways for s and number of ways for t. So, in this way to solve this particular type of problem.
Maths-
A rectangle has sides of (2m – 1) & (2n – 1) units as shown in the figure composed of squares having edge length one unit then no. of rectangles which have odd unit length –
A rectangle has sides of (2m – 1) & (2n – 1) units as shown in the figure composed of squares having edge length one unit then no. of rectangles which have odd unit length –
Maths-General
chemistry-
Observe the esterification mechanisms for primary and tertiary alcohols
Type-1:
Type-2:
Mechanism:
In the above reaction (P) and (Q) are respectively :
Observe the esterification mechanisms for primary and tertiary alcohols
Type-1:
Type-2:
Mechanism:
In the above reaction (P) and (Q) are respectively :
chemistry-General
physics-
Two identical samples of a gas are allowed to expand (i) isothermally (ii) adiabatically work done is
Two identical samples of a gas are allowed to expand (i) isothermally (ii) adiabatically work done is
physics-General
physics-
A thermodynamic system is taken from state A to B along ACB and is brought back to Along BDA as Shown in the PV diagram. The net work done during the complete cycle is given by the area.
A thermodynamic system is taken from state A to B along ACB and is brought back to Along BDA as Shown in the PV diagram. The net work done during the complete cycle is given by the area.
physics-General
physics-
An ideal gas is taken V path ACBA as Shown in figure, The net work done in the whole cycle is
An ideal gas is taken V path ACBA as Shown in figure, The net work done in the whole cycle is
physics-General